Pion Reaction: Learn About e⁻+n→e⁻+p⁺+π⁻

[luisgml_2000]

Hello.

I've been having a hard time finding information about the following reaction:

e$$^{-}$$+n$$\rightarrow$$e$$^{-}$$+p$$^{+}$$+$$\pi$$$$^{-}$$

I hope you could give me some information about it.

I'm interested in energies for the incident e$$^{-}$$ above 200MeV.

I think it has to do something with hypothetical quark production, bu I'm not sure.

Thank you.

 

[Norman]

I would google "pion electroproduction" and maybe add "near threshold" since the threshold of that reaction is about 150 MeV.

What are you interested in? The theoretical understanding of the process? Experiments that extract information about it?

You asked a very broad question about a very specific reaction... which tends to not get you much help around here.

 

[sir-pinski]

Hello there,

Thank you for reaching out about the pion reaction e^{-}+n\rightarrowe^{-}+p^{+}+\pi^{-}. This reaction involves an electron (e^{-}) and a neutron (n) colliding, resulting in the production of an electron (e^{-}), a proton (p^{+}), and a negative pion (\pi^{-}).

This reaction is often studied in high-energy physics experiments, where the incident electron has an energy above 200 MeV. At these high energies, the electron interacts with the neutron through the strong nuclear force, resulting in the production of the proton and pion. This reaction is important in understanding the structure of the nucleon (proton and neutron) and the behavior of the strong force.

As you mentioned, this reaction also has implications for the production of hypothetical quarks. Quarks are fundamental particles that make up protons and neutrons, and in some theories, they can also exist as free particles. In this reaction, the high-energy electron can interact with the quarks inside the neutron, producing the proton and pion as a result.

I hope this information helps in your understanding of the pion reaction. If you have any further questions, please don't hesitate to ask. Best of luck in your studies!