Please solve the decibel problem

  • Thread starter taoz
  • Start date
In summary: Bm is a unit for expressing power. It is the ratio of a power level to a reference power level, but that makes it a measurement of power. It has no units because it IS a unit. When you see a decibel reference in the wild, there are TWO numbers to consider, the number of decibels, and whatever reference it compares to. Thus the letter m after the dB refers to one milliwatt. That milliwatt could be at any impedance. Old signal generators used to refer to voltages at 50 ohms. Then someone figured out that these numbers made a hell of a lot more sense if you listed them in terms of dBm. Analog phone systems often derive dBm from
  • #1
taoz
4
0
10dB+10dB=20dB
10dB+1dB=11dB ??
10dBm+10dB=20dBm
10dBm+1dB=11dBm ??
Is all correct? and what is the difference with dB+dB and dBm+dB?
 
Engineering news on Phys.org
  • #2
taoz said:
10dB+10dB=20dB
10dB+1dB=11dB ??
10dBm+10dB=20dBm
10dBm+1dB=11dBm ??
Is all correct? and what is the difference with dB+dB and dBm+dB?
How about you look up the definitions and how to convert from one to the other.
 
  • #3
I believe this has been covered on PF already. A search should bring results. dB represents gain or loss. dB with a suffix is an absolute. For instance, 0 dBm is .001 watts into a specified impedance. Often it is 50 ohms. I believe the telephone system my have a similar 600 ohm standard.
 
  • #4
Averagesupernova said:
I believe the telephone system my have a similar 600 ohm standard.
indeed, the world famous and much revered Simpson 260 has a db scale referred to 1mw/600 ohms, see lower left
simpson_260-7prt_02.jpg


image from http://simpson260.com
 
  • #5
taoz said:
10dB+10dB=20dB
10dB+1dB=11dB ??
10dBm+10dB=20dBm
10dBm+1dB=11dBm ??
Is all correct? and what is the difference with dB+dB and dBm+dB?
so @taoz, did you do as phinds suggested and look up the difference between dB and dBm ?
what did you discover ?

Dave
 
  • #6
taoz said:
...what is the difference with dB+dB and dBm+dB?

When you see a decibel reference in the wild, there are TWO numbers to consider, the number of decibels, and whatever reference it compares to. Thus the letter m after the dB refers to one milliwatt. That milliwatt could be at any impedance. Old signal generators used to refer to voltages at 50 ohms. Then someone figured out that these numbers made a hell of a lot more sense if you listed them in terms of dBm. Analog phone systems often derive dBm from RMS voltage measurements at 600 ohms.

When dealing with transmitters you sometimes see references to dBW (one watt). When dealing with antennas you often see gain references to an isotropic radiator (radiates equally in all directions). Among ham radio operators you often see reference to antenna gain compared to a dipole, which has a theoretical gain of 2.2 dB more than an isotropic radiator.

There are other references. I used to work on analog frequency division multiplex systems for phone trunks. There is dBrn (dB referenced to the noise floor), dBrnC (C-message wieghting on a 3400 Hz Channel referenced to the noise floor), dBrnC0 (this was dynamic range of the channel from the Test Level Point, or maximum power, to the noise floor with C-message weighting). You can get wild with all these references and they are commonly used in many system designs. And don't get me started about psophometric versus C-message weighting...

So when someone casually tosses the word decibel around your inner engineer should scream Decibels over WHAT?

I taught this to my teen-age daughter and now she taunts her high school teachers with that question every time they discuss decibels. If she gets it, so can you.
 
  • #7
A signal that is 10dB greater than 5 dBm happens to be 15 dBm.

dBm is a measurement of power. It is the ratio of a power level to a reference power level, but that makes it a measurement of power. It has no units because it IS a unit.
Asking for the units of dBm is like asking what are the units for an inch. dBm is a unit for expressing power. You can convert it to watts if you like.

dB expresses a ratio between power levels, with no information as to what those levels were. It has no units because it is simply a ratio. You can not convert it to anything, but it is a useful ratio if you apply it to a known power level.
 

FAQ: Please solve the decibel problem

What is the decibel problem?

The decibel problem is a mathematical problem that involves converting a ratio of two power values into a logarithmic scale, which is used to measure the intensity of sound or electrical signals.

How do you solve the decibel problem?

The decibel problem can be solved by using the formula dB = 10 log (P1/P2), where P1 is the initial power value and P2 is the final power value. This will give you the decibel value, which represents the ratio of the two power values.

Why is the decibel problem important?

The decibel problem is important because it allows us to accurately measure and compare the intensity of sound or electrical signals. It is commonly used in telecommunications, audio engineering, and physics.

Can you give an example of solving the decibel problem?

Sure, for example, if the initial power value is 1 watt and the final power value is 0.1 watt, the decibel value would be 10 log (1/0.1) = 10 log (10) = 10 x 1 = 10 decibels.

Are there any common mistakes when solving the decibel problem?

Yes, some common mistakes when solving the decibel problem include using the wrong formula, not converting the power values into watts, and not converting the decibel value into a ratio. It is important to carefully follow the formula and units when solving this problem.

Back
Top