- #1
JavaJoeUK2011
- 6
- 0
A horizontal force of 80N acts on a mass of 6Kg resting on a horizontal surface. The mass is initially at rest and covers a distance of 5m in 0.92s under the action of the force. Assuming there are no energy losses due to air resistance and therefore that the acceleration is constant.
1.Plot a graph of the kinetic energy of the mass against time.
d = (1/2)at2 = (1/2)(11.81474m/s2)(0.92s)2 = 5m
v= 11.814 m/s2
KE = 1/2 mv^2 = 1/2 x 6 x 11.814^2 = 418.117
So x-axis would be KE of Mass 0 to 418.177 and y-axis would be time 0 to .092
2.Plot a graph of the kinetic energy of the mass against distance.
So x-axis would be KE of Mass 0 to 418.177 and y-axis would be Distance 0 to .5
Have i done this correctly?
1.Plot a graph of the kinetic energy of the mass against time.
d = (1/2)at2 = (1/2)(11.81474m/s2)(0.92s)2 = 5m
v= 11.814 m/s2
KE = 1/2 mv^2 = 1/2 x 6 x 11.814^2 = 418.117
So x-axis would be KE of Mass 0 to 418.177 and y-axis would be time 0 to .092
2.Plot a graph of the kinetic energy of the mass against distance.
So x-axis would be KE of Mass 0 to 418.177 and y-axis would be Distance 0 to .5
Have i done this correctly?