- #1
dpeagler
- 34
- 0
I have been trying to plot a vector and it's derivative for a while now, but I cannot figure out why I can't get them to plot.
Here is what I put for my code...
a[t_] := Sin[t] Cos[2 t]
b[t_] := Sin[t] Sin[2 t]
c[t_] := Cos[t]
V[t_] := {a, b, c}
I tried this...
ParametricPlot[{a[t], b[t], c[t]}, {a'[t], b'[t], c'[t]}, {t, -\[Pi]/2, \[Pi]/2}, {t, \[Pi]/4}]
and this...
ParametricPlot[{V[t]},{V'[\[Pi]/4]},{{t, -\[Pi]/2, \[Pi]/2}
The function is seen as V[t]. I want to graph it from -Pi/2 to Pi/2 and I want to have V'[Pi/4] on the same graph. And then I want to have two different images.
I know that's a lot, but I'm sure it's something really simple that I'm missing. Thanks to anyone who can give any advice.
Here is what I put for my code...
a[t_] := Sin[t] Cos[2 t]
b[t_] := Sin[t] Sin[2 t]
c[t_] := Cos[t]
V[t_] := {a, b, c}
I tried this...
ParametricPlot[{a[t], b[t], c[t]}, {a'[t], b'[t], c'[t]}, {t, -\[Pi]/2, \[Pi]/2}, {t, \[Pi]/4}]
and this...
ParametricPlot[{V[t]},{V'[\[Pi]/4]},{{t, -\[Pi]/2, \[Pi]/2}
The function is seen as V[t]. I want to graph it from -Pi/2 to Pi/2 and I want to have V'[Pi/4] on the same graph. And then I want to have two different images.
I know that's a lot, but I'm sure it's something really simple that I'm missing. Thanks to anyone who can give any advice.