Point of Inflection: Analyze x^2/x-1

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In summary, the conversation discusses the derivative of the function f(x) = x^2/(x - 1) and how to identify asymptotes, extrema, and points of inflection. The suggested method for finding the derivative is to use the product and chain rule. It is concluded that there is no point of inflection since the equation cannot be set equal to zero. However, it is also mentioned that the sign of the second derivative changes at x = 1, which could indicate an inflection point.
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mathpat
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Homework Statement



x^2 / x-1. Identify any asymptotes, extrema and points of inflection.

Homework Equations





The Attempt at a Solution



I am stuck trying to derive my first derivative. My first derivative equals x(x-2)/(x-1)^2. I tried to use the quotient rule again using while incorporating the chain rule and after multiple attempts I kept resulting with 2 / (x-1)^3.

Any suggestions?
 
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  • #2
This should help in general, switch your quotient rule into a product & chain rule :

##\frac{x^2}{x-1} = x^2 (x-1)^{-1}##
 
  • #3
mathpat said:

Homework Statement



x^2 / x-1. Identify any asymptotes, extrema and points of inflection.
Write this as an equation, and use parentheses.

f(x) = x2/(x - 1)
mathpat said:

Homework Equations





The Attempt at a Solution



I am stuck trying to derive my first derivative. My first derivative equals x(x-2)/(x-1)^2.
As an equation, this is f'(x) = x(x-2)/(x-1)2.
mathpat said:
I tried to use the quotient rule again using while incorporating the chain rule and after multiple attempts I kept resulting with 2 / (x-1)^3.

Any suggestions?
Your answer is correct, and this can be verified by calculating the derivative using the technique that Zondrina suggested.
 
  • #4
I see... so basically that means there is no point of inflection since I can not set that equation equal to zero and solve?


By the way, I appreciate both of your help.
 
  • #5
mathpat said:
I see... so basically that means there is no point of inflection since I can not set that equation equal to zero and solve?
The sign of f'' changes at x = 1. If x < 1, f''(x) < 0, and if x > 1, f''(x) > 0. Does this mean that there is an inflection point at x = 1? Why or why not?
mathpat said:
By the way, I appreciate both of your help.
 

FAQ: Point of Inflection: Analyze x^2/x-1

What is a point of inflection?

A point of inflection is a point on a graph where the curve changes from being concave upwards to concave downwards, or vice versa. In other words, it is the point where the curvature of the graph changes.

How do you find the point of inflection for x^2/x-1?

To find the point of inflection for x^2/x-1, we need to take the second derivative of the function and set it equal to zero. This will give us the x-value of the point of inflection. Then, we can plug this x-value back into the original function to find the corresponding y-value.

What is the significance of a point of inflection?

A point of inflection is significant because it indicates a change in the direction of the curve. It can also help us identify the minimum or maximum points of a function.

Can a function have more than one point of inflection?

Yes, a function can have more than one point of inflection. This occurs when the curve changes direction multiple times, resulting in multiple points where the curvature changes.

How do you graph a function with a point of inflection?

To graph a function with a point of inflection, we first need to find the x and y values of the point of inflection. Then, we can plot these coordinates on the graph and use the direction of the curve to determine the shape of the graph on either side of the point of inflection.

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