Poisson's equation, properties of eigenvalues

In summary: L^2$-norm. Therefore, for the Dirichlet problem, the eigenvalues are positive, and for the Neumann problem, they are non-negative. In summary, for a given equation Δu = -λu with either the Dirichlet or Ne
  • #1
linda300
61
3
hello,

Let T be a open, connected and bounded subset of ℝ3 which has a smooth boundary bd(T).

Consider the equation Δu = -λu with either the Dirichlet condition (u=0 in bd(T)) or Neumann (where δu/δn = 0 on bd(T)).

Define:

[itex] \left\langle g,h \right\rangle =\iiint_{T}{g(x)h^{*}(x)}dx[/itex]
where * means conjugate

Show that for a Dirichlet problem the eigenvalues are positive and that for a Neumann problem they are not negative.

So the first greens identity is

[itex] \iint_{bd(T)}{v\frac{\partial u}{\partial n}}dS=\iiint_{T}{\nabla v\cdot \nabla u\,d\vec{x}}+\iiint_{T}{v\Delta u\,d\vec{x}} [/itex]

using this with v=u,

for a Dirichlet problem,

u=0 on the boundary so

[itex] 0=\iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}+\iiint_{T}{u\Delta u\,d\vec{x}} [/itex]

then

[itex] \iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}=\lambda \iiint_{T}{{{u}^{2}}\,d\vec{x}} [/itex]

is that correct?

and its the same result for the Neumann problem except the du/dn term is zero on the boundary so i can't really see how to get that the eigenvalues are positive, or non negative,

is this not the correct approach?
 
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  • #2
Thank you Yes, that is the correct approach. For the Dirichlet problem, we have: \begin{align}0 &= \iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}+\iiint_{T}{u\Delta u\,d\vec{x}} \\&= \iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}-\lambda \iiint_{T}{{{u}^{2}}\,d\vec{x}} \end{align}Using the definition of the inner product: \begin{align}0 &= \left\langle \nabla u, \nabla u \right\rangle - \lambda\left\langle u, u \right\rangle \\&= \| \nabla u \|^2 - \lambda \| u \|^2 \\ &= \| \nabla u \|^2 - \lambda \| u \|_2^2 \\ &\geq 0 \end{align}where $\| \cdot \|$ is the usual vector norm, and $\| \cdot \|_2$ is the $L^2$-norm. For the Neumann problem, we have: \begin{align}0 &= \iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}+\iiint_{T}{u\Delta u\,d\vec{x}} \\&= \iiint_{T}{\nabla u\cdot \nabla u\,d\vec{x}}-\lambda \iiint_{T}{{{u}^{2}}\,d\vec{x}} \end{align}Using the definition of the inner product: \begin{align}0 &= \left\langle \nabla u, \nabla u \
 

Related to Poisson's equation, properties of eigenvalues

1. What is Poisson's equation?

Poisson's equation is a partial differential equation that describes the relationship between the distribution of electric charge in a region and the electric potential created by that charge. It is commonly used in electrostatics and in solving problems involving electric fields.

2. What are the properties of eigenvalues?

Some key properties of eigenvalues include: they are always real numbers, they represent the possible values of a particular variable in a system, they are invariant under a change of basis, and they are often used to characterize the behavior of a system.

3. How is Poisson's equation related to eigenvalues?

Poisson's equation can be solved using eigenvalues and eigenvectors. The solutions to the equation are the eigenvalues, and the corresponding eigenvectors represent the electric potential in the system.

4. What is the physical interpretation of eigenvalues in Poisson's equation?

The eigenvalues in Poisson's equation represent the possible values of the electric potential in a given system. These values determine the behavior of the electric field and can provide insight into the distribution of electric charge in a region.

5. How are eigenvalues used in practical applications?

Eigenvalues have many practical applications, including solving problems in physics, engineering, and computer science. They are used to analyze the behavior of systems, determine stability, and find optimal solutions in various fields such as signal processing, image processing, and machine learning.

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