- #1
skrat
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Homework Statement
Elliptically polarized light, where the rotation of the ellipse is ##\pi/6## and its major axis is ##2E_0## and minor axis ##E_0##, is left through a polarization foil. The foil transmits light in ##x## axis (a) and in ##y## axis (b). Calculate the ratio of transmitted light (intensity) in both cases (a) and (b).
Homework Equations
The Attempt at a Solution
Ok, If my ellipse is rotated by an angle ##\pi/6## than in my original coordinate system:
##E_x={E_x}'\cos \varphi +{E_y}'\sin\varphi## and
##E_Y=-{E_x}'\sin\varphi +{E_y}'\cos \varphi##.
Knowing that ##{E_x}'=2E_0## and ##{E_y}'=E_0## the amplitudes above can be written as: $$E_X=E_0(\sqrt 3+1/2)$$ and $$E_y=E_0(\sqrt{3}/2-1)$$.
The intensity before the polarization foil is ##(2E_0)^2+E_0^2=5E_0^2##. Than the ratio is
(a) ##\frac{|E_x|^2}{5E_0^2}=0.9964## and
(b) ##\frac{|E_y|^2}{5E_0^2}=0.00358##.
Or is this completely wrong?