- #1
nichmetsa
- 3
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- TL;DR Summary
- (1/(1-n))*(p1v1-p2v2) into (n/(n-1))*(p1v1-p2v2)
Hello there,
So yesterday my thermodynamics professor did some black magic and transformed our beloved equation (1/(1-n))*(p1v1-p2v2) into (n/(n-1))*(p1v1-p2v2), but i didnt understand why he did it and how (he is too fast for my writing). Does anyone know how he did it, are there any restrictions to this formula? Just for context he was doing a introduction to the Rankine Cycle.
So yesterday my thermodynamics professor did some black magic and transformed our beloved equation (1/(1-n))*(p1v1-p2v2) into (n/(n-1))*(p1v1-p2v2), but i didnt understand why he did it and how (he is too fast for my writing). Does anyone know how he did it, are there any restrictions to this formula? Just for context he was doing a introduction to the Rankine Cycle.