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09jml90
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Homework Statement
The position of a particle as a function of time (in s) is given by C1 + C2t + C3t2.
Let C1 = 19.0 m, C2 = 39.1 m/s, and C3 = -0.62 m/s2.
(a) What is the velocity of the particle at time t = 13.0 s?
(b) What is the particle's acceleration at time t = 13.0 s?
Homework Equations
C1 + C2t + C3t2.
Let C1 = 19.0 m, C2 = 39.1 m/s, and C3 = -0.62 m/s2.
The Attempt at a Solution
I wasn't sure how to do this problem from the beginning, so I tried playing around with some numbers to see if anything could come up. I tried substituting 13.0 into the formula to create a quadratic equation and got: -104.78x2 + 508.3x + 19. I then used the quadratic formula to get some points: (-0.037, 0.0495) (4.888, 0.06186). If I'm doing anything right so far, I would say from the graph that the velocity is decreasing and the acceleration is negative?
Any help would be greatly appreciated. Thank you.