- #1
PSN03
- 100
- 9
- Homework Statement
- A thin convex lens L (refractive index = 1.5) is placed on a plane mirror M. When a pin is placed at A, such that OA = 18 cm, its real inverted image is formed at A itself, as shown in figure. When a liquid of refractive index μl is put between the lens and the mirror, the pin has to be moved to A', such that OA' = 27 cm, to get its inverted real image at A' itself. The value of μl will be ?
- Relevant Equations
- 1/f=(μ-1)(1/R-1/R')
I know how to solve the problem but the only thing that's bothering me is what is A?
According to me A is should be 2F ie 2 times the focal length distance. I thought of it like this:
1. First there will be an image formed due to the lens.
2. The image will be formed below the lens but the mirror will reflect the image and the final image will be formed at A again.
3. Since the image formed in the end is inverted and at the same position, hence the distance is 2F.
Am I thinking in the right way? Cause I am not able to get the right answer.
According to me A is should be 2F ie 2 times the focal length distance. I thought of it like this:
1. First there will be an image formed due to the lens.
2. The image will be formed below the lens but the mirror will reflect the image and the final image will be formed at A again.
3. Since the image formed in the end is inverted and at the same position, hence the distance is 2F.
Am I thinking in the right way? Cause I am not able to get the right answer.