Possible energy values given Hamiltonian

In summary, the document discusses how to determine possible energy values of a quantum system using its Hamiltonian operator. It explains that the Hamiltonian encapsulates the total energy of the system, and by solving the corresponding Schrödinger equation, one can find the eigenvalues, which represent the allowed energy levels. The analysis also highlights the significance of boundary conditions and the role of potential energy in shaping the energy spectrum.
  • #1
Rayan
17
1
Homework Statement
The Hamiltonian for a two level system with the orthonormal states |1⟩ and |2⟩ is given by:
Relevant Equations
H = a|1⟩⟨1| + b|1⟩⟨2| + b|2⟩⟨1| + c|2⟩⟨2| ,

where a,b and c are real constants with energy unit.
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$

And tried to find the eigenvalues/energies of H, so I solved

$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$

but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$

What am I doing wrong here?
 
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  • #2
Rayan said:
So first I rewrote H as a matrix:

$$ H =
\begin{pmatrix}
a & b \\
b & c
\end{pmatrix} $$
Ok.

Rayan said:
And tried to find the eigenvalues/energies of

$$ H - \lambda I $$
Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.

Rayan said:
but got a complicated solution
$$ \lambda = \frac{a-c}{2} \pm \sqrt{ ( \frac{a-c}{2} )^2 - (ac-b^2) } $$
What am I doing wrong here?
It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
 
  • #3
TSny said:
Ok.Terminology: You want the eigenvalues of ##H##, not ##H - \lambda I##.It's hard to tell where you made the mistakes. Please show the steps in getting the quadratic equation for ##\lambda## and then the steps in solving for ##\lambda##.
You're right! I just updated my question with the steps!:)
 
  • #4
Rayan said:
$$ det (H - \lambda I ) =
\begin{vmatrix}
a-\lambda & b \\
b & c-\lambda
\end{vmatrix} = (a-\lambda)(c-\lambda) - b^2 = ac - a\lambda - c\lambda + \lambda^2 - b^2 = 0
$$
This looks good.

Rayan said:
but got a complicated solution

$$ \lambda = \frac{a+c}{2} \pm \sqrt{ ( \frac{a+c}{2} )^2 - (ac-b^2) } $$
This looks correct.

My preference would be to write what you have as $$ \lambda = \frac{a+c}{2} \pm \frac1 2 \sqrt{ ((a+c)^2 - 4(ac-b^2) } $$
You should be able to simplify the expression inside the square root a little. (Work with the terms involving ##a## and ##c##.)
 

FAQ: Possible energy values given Hamiltonian

What is a Hamiltonian in the context of quantum mechanics?

In quantum mechanics, the Hamiltonian is an operator corresponding to the total energy of the system. It includes both kinetic and potential energy components and is usually denoted by H. The Hamiltonian plays a crucial role in determining the evolution of a quantum system over time.

How are the possible energy values of a system determined from its Hamiltonian?

The possible energy values of a system, also known as eigenvalues, are determined by solving the Schrödinger equation Hψ = Eψ, where H is the Hamiltonian operator, ψ is the eigenfunction (or wavefunction), and E is the eigenvalue corresponding to the energy. The solutions to this equation give the quantized energy levels of the system.

What is the significance of eigenvalues and eigenfunctions in this context?

Eigenvalues represent the possible energy levels that a quantum system can occupy, while eigenfunctions represent the corresponding quantum states of the system. Each eigenvalue is associated with a specific eigenfunction, and together they describe the allowed states and energies of the system.

Can the Hamiltonian have both discrete and continuous energy spectra?

Yes, the Hamiltonian can have both discrete and continuous energy spectra. Discrete spectra typically arise in bound systems, such as electrons in an atom, where the energy levels are quantized. Continuous spectra occur in unbound systems, such as a free particle, where the energy can take on a continuous range of values.

How does the form of the Hamiltonian affect the energy levels of a system?

The form of the Hamiltonian, which includes the specific kinetic and potential energy terms, determines the nature of the energy levels. For example, a simple harmonic oscillator has a Hamiltonian that leads to equally spaced energy levels, while the hydrogen atom's Hamiltonian results in energy levels that follow a specific inverse-square law. The potential energy term, in particular, plays a significant role in shaping the energy spectrum.

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