- #1
tomasblender
- 3
- 0
Homework Statement
A 0.0145 kg, 2.18 m long wire is fixed at both ends and vibrates in its simplest mode under a tension of 201 N. When a tuning fork is placed near the wire, a beat frequency of 4.85 Hz is heard. What are the possible frequencies of the tuning fork? (enter the smaller frequency first)
Homework Equations
f = v / 2L = (Ts / u )^0.5 / 2L = (Ts*L/m)/2L
f(beat) = |f1-f2|
The Attempt at a Solution
(201N * 2.18m /0.00145kg )^.5 / (2 * 2.18 m ) + 4.85 Hz = 130.93 Hz
(201N * 2.18m /0.00145kg )^.5 / (2 * 2.18 m ) - 4.85 Hz = 121.23 Hz
This is incorrect and i cannot think of what else to do / try
Thanks :D