Possible outcomes of angular momentum state

In summary, the problem involves finding the possible outcomes and probabilities for measuring the x component of angular momentum in a state described by the wavefunction \psi = R(r)(\sqrt{\frac{1}{3}}Y_{11} + i\sqrt{\frac{2}{3}}Y_{10}), which can be solved by finding the matrix representation of Lx and then finding the eigenvalues and eigenvectors. The spherical harmonics are not eigenstates, so you must find linear combinations that are eigenstates of Lx.
  • #1
EricTheWizard
14
0

Homework Statement


A particle is in the state [itex]\psi = R(r)(\sqrt{\frac{1}{3}}Y_{11} + i\sqrt{\frac{2}{3}}Y_{10})[/itex]]. If a measurement of the x component of angular momentum is made, what are the possible outcomes and what are the probabilites of each?

Homework Equations


[tex]L_{\pm}Y_{lm}=\sqrt{l(l+1)-m(m \pm 1)}Y_{l(m\pm 1)}[/tex]
[tex]L_x = \frac{1}{2}(L_+ + L_-)[/tex]
[tex]\psi = \sum \alpha_{lm} Y_{lm}[/tex]

The Attempt at a Solution


I understand how to get the expectation value of [itex]L_x[/itex] for the entire wavefunction through the inner product [itex]\langle \psi |L_x| \psi \rangle[/itex] and how to get the Fourier coefficients for the state probabilities, but I don't see how to get the "possible outcomes". Expectation values of individual eigenstates [itex]\langle Y_{lm} |L_x| L_{lm} \rangle[/itex] are always equal to 0, so I don't see how you can measure any outcome but 0 for definite eigenstates. Shouldn't the only outcome be the expectation value of the entire wavefunction?
 
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  • #2
You need to expand the state in terms of the eigenfunctions of Lx.
 
  • #3
vela said:
You need to expand the state in terms of the eigenfunctions of Lx.

Could you explain this a bit more? I was under the impression that there were no [itex]L_x Y_{lm}[/itex] eigenstates because the effect of the operator on the spherical harmonics is to raise and lower the "m" index, a la [itex]L_x Y_{lm} = \frac{1}{2}(L_+ +L_-)Y_{lm} = \frac{\hbar}{2}(\sqrt{l(l+1)-m(m+1)}Y_{l(m+1)}+\sqrt{l(l+1)-m(m-1)}Y_{l(m-1)})[/itex], changing the basis vectors. Taking the expectation value of the entire wavefunction only leads to 0 as well, so I'm starting to think that that's it.
 
  • #4
That's right. The spherical harmonics are not eigenstates. You have to find linear combinations which are eigenstates of Lx.
 
  • #5
Is it valid to just take x as equivalent to the z direction (since the coordinates are arbitrary anyways) and define [itex]L_x Y_{lm} = m \hbar Y_{lm}[/itex] and just solve it that way?
 
  • #6
No, it's not. The wave function as written implies a coordinate system, and the problem is asking you questions with respect to this coordinate system.

Find the matrix representation of Lx, and then find the eigenvalues and eigenvectors of that matrix.
 

FAQ: Possible outcomes of angular momentum state

1. What is angular momentum state?

Angular momentum state refers to the state of a physical system characterized by the amount and direction of angular momentum it possesses. Angular momentum is a measure of rotational motion and is conserved in closed systems.

2. How is angular momentum state calculated?

Angular momentum state can be calculated by multiplying the moment of inertia of a rotating object by its angular velocity. This can also be expressed as the product of the object's mass, radius, and tangential velocity.

3. What are the possible outcomes of angular momentum state?

The possible outcomes of angular momentum state depend on the specific physical system. In general, the angular momentum state can remain constant, increase, or decrease depending on the forces acting on the system.

4. How does angular momentum state affect the behavior of a system?

Angular momentum state affects the behavior of a system by determining its rotational motion. A change in angular momentum state can result in a change in rotational speed or direction of the system.

5. Can angular momentum state be changed?

Yes, angular momentum state can be changed by applying an external torque or force to the system. This can result in an increase, decrease, or even a reversal of the system's rotational motion.

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