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sonastylol
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[SOLVED] Angle between vectors:
What is the angle between A and B ? Answer in units of degree.
From the previous problem:
A = 1.02 units long in positive y direction [0i + 1.02j]
B = [-6.18i + 3.64j]
I got the question from the previous part right, finding scalar product of the 2 vectors. So I know the vectors are set up correctly.
I am under the impression that [tex]\theta[/tex] = [tex]\theta[/tex]b - [tex]\theta[/tex]a
Arctan of (-1.02/0 ) gives an error ( obviously ) so i just did arctan of (-1.02) = 45.567 degrees
Arctan of (3.64 / -6.18 ) gives a degree of -30.497
When doing the answer, I got [tex]\theta[/tex] = 76.064. I tried this as both a negative and a positive and I was wrong.
What am I missing here? Is one angle supposed to change sign? Is my order wrong? Maybe my arctan of (1.02) is wrong?
Thanks
Homework Statement
What is the angle between A and B ? Answer in units of degree.
Homework Equations
From the previous problem:
A = 1.02 units long in positive y direction [0i + 1.02j]
B = [-6.18i + 3.64j]
The Attempt at a Solution
I got the question from the previous part right, finding scalar product of the 2 vectors. So I know the vectors are set up correctly.
I am under the impression that [tex]\theta[/tex] = [tex]\theta[/tex]b - [tex]\theta[/tex]a
Arctan of (-1.02/0 ) gives an error ( obviously ) so i just did arctan of (-1.02) = 45.567 degrees
Arctan of (3.64 / -6.18 ) gives a degree of -30.497
When doing the answer, I got [tex]\theta[/tex] = 76.064. I tried this as both a negative and a positive and I was wrong.
What am I missing here? Is one angle supposed to change sign? Is my order wrong? Maybe my arctan of (1.02) is wrong?
Thanks