Potassium Iodide as a catalyst for Hydrogen Peroxide

  • Thread starter Thread starter tongangeline_657
  • Start date Start date
  • Tags Tags
    Catalyst
Click For Summary
The discussion centers on the reaction between potassium iodide (KI) and hydrogen peroxide (H2O2). It clarifies that potassium iodide acts differently than a traditional catalyst, as it is consumed in the reaction and transforms into iodide. The reaction is identified as a redox process, where iodide is oxidized to iodine (I2) in both acidic and alkaline conditions. In acidic solutions, the reaction is represented by the equation 2I- + H2O2 + 2H+ → I2 + 2H2O. In alkaline solutions, iodine can further oxidize hydrogen peroxide to produce oxygen, leading to the overall reaction of 2H2O2 → O2 + 2H2O. This highlights the dual role of iodine in the reaction mechanism.
tongangeline_657
Messages
1
Reaction score
0
Hey, I am having trouble understanding the type of reaction that occurs between potassium iodide, and hydrogen peroxide. A website I looked at said that potassium iodide was a catalyst for Hydrogen peroxide, but potassium iodide doesn't work in the same way that a catalyst described by a textbook does, as it gets 'used up' and becomes Iodide, hence it is more like a redox reaction. Could someone please help explain? I am really curious!
 
Chemistry news on Phys.org
tongangeline_657 said:
Hey, I am having trouble understanding the type of reaction that occurs between potassium iodide, and hydrogen peroxide. A website I looked at said that potassium iodide was a catalyst for Hydrogen peroxide, but potassium iodide doesn't work in the same way that a catalyst described by a textbook does, as it gets 'used up' and becomes Iodide, hence it is more like a redox reaction. Could someone please help explain? I am really curious!
Answering your three two questions in order: inadequate reference; yes, you've understood correctly.
 
Depends on the pH. In acidic solution, iodide is oxidised to iodine:
2I- + H2O2 + 2H+ → I2 + 2H2O
In alkaline solution, the same oxidation occurs, but I2 can also oxidise H2O2 to oxygen:
2I- + H2O2 → I2 + 2OH-
I2 + H2O2 + 2OH- → 2I- + O2 + 2H2O
Overall 2H2O2 → O2 + 2H2O
 
I came.across a headline and read some of the article, so I was curious. Scientists discover that gold is a 'reactive metal' by accidentally creating a new material in the lab https://www.earth.com/news/discovery-that-gold-is-reactive-metal-by-creating-gold-hydride-in-lab-experiment/ From SLAC - A SLAC team unexpectedly formed gold hydride in an experiment that could pave the way for studying materials under extreme conditions like those found inside certain planets and stars undergoing...

Similar threads

Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
7K
  • · Replies 1 ·
Replies
1
Views
10K
  • · Replies 2 ·
Replies
2
Views
22K
  • · Replies 3 ·
Replies
3
Views
17K
Replies
6
Views
8K
Replies
1
Views
7K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 5 ·
Replies
5
Views
24K