- #1
Lindsayyyy
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Hi everyone I have the following problem:
Give is the following potential for a molecule:
[tex]E_s(R)=E_s(\infty)-\frac {1}{R}+A*exp(-cR)[/tex]
whereas E_s(infinity)=1.49 eV. A and c are constants which I want to calculate. R(equilibrium) is given as 2.36 Angström and the wave number for the lowest state is v=364,6 cm^-1
So far so good I already got the solution for this, but I have troubles concerning the units. If you take a look at the potential you have 1/R [m^-1] and E_s(infninity) whichs unit is [eV].
When I try to calculate c I derive the potential and use that the second derivation is the feather constant. I come to:
[tex] c=k*{R_0}^2 +\frac {2}{R_0}[/tex]
whereas k is the feather constant and R0 the radius at the equilibrium.
The soluton for k should be: 0.0698 atomic units.
But I have no idea how to get there. I'm also conernced about the units because I only knew about N/m or kg/s^2 for k.
Can anyone help me with this?
Thanks in advance
Homework Statement
Give is the following potential for a molecule:
[tex]E_s(R)=E_s(\infty)-\frac {1}{R}+A*exp(-cR)[/tex]
whereas E_s(infinity)=1.49 eV. A and c are constants which I want to calculate. R(equilibrium) is given as 2.36 Angström and the wave number for the lowest state is v=364,6 cm^-1
Homework Equations
The Attempt at a Solution
So far so good I already got the solution for this, but I have troubles concerning the units. If you take a look at the potential you have 1/R [m^-1] and E_s(infninity) whichs unit is [eV].
When I try to calculate c I derive the potential and use that the second derivation is the feather constant. I come to:
[tex] c=k*{R_0}^2 +\frac {2}{R_0}[/tex]
whereas k is the feather constant and R0 the radius at the equilibrium.
The soluton for k should be: 0.0698 atomic units.
But I have no idea how to get there. I'm also conernced about the units because I only knew about N/m or kg/s^2 for k.
Can anyone help me with this?
Thanks in advance