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A system consists of three particles, each of mass 4.00 g, located at the corners of an equilateral triangle with sides of 36.0 cm.
(a) Calculate the potential energy of the system.
m = .004, d = .2078
UG = Gm1m2/R
U_total = sum of U_i
U_total = Gm1m2/R + Gm1m3/R + Gm2m3/R
U_total = [((6.67300E-11)(.004)(.004))/(.2078)] * 3
U_total = 1.5414E-14
Final answer is incorrect. Any ideas?
(a) Calculate the potential energy of the system.
m = .004, d = .2078
UG = Gm1m2/R
U_total = sum of U_i
U_total = Gm1m2/R + Gm1m3/R + Gm2m3/R
U_total = [((6.67300E-11)(.004)(.004))/(.2078)] * 3
U_total = 1.5414E-14
Final answer is incorrect. Any ideas?
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