- #1
Hardik Batra
- 130
- 5
As shown in figure, we know that at the sharp end E field is strong, and at the other end field is weak.
Inside the conductor E=0. that means V=constant. on its surface and throughout the conductor.
if we move unit positive charge from B to A or P to Q (as shown in fig.) then different amount of work will have to do to bring this charge (because field intensity is different at both the ends).
(assumed distance between PQ = distance AB)
According to the definition of Potential,
Work done (against the field ) to bring unit positive charge from infinite distance to point in the electric field is called electric potential at that point.
Here, Work done will be more to move B to A rather than P to Q because field is strong(at B to A) therefore more work will to do.
So the potential is different at point A and at point Q?(it is not the same throughout the conductor.)
If i wrong please correct me...
Inside the conductor E=0. that means V=constant. on its surface and throughout the conductor.
if we move unit positive charge from B to A or P to Q (as shown in fig.) then different amount of work will have to do to bring this charge (because field intensity is different at both the ends).
(assumed distance between PQ = distance AB)
According to the definition of Potential,
Work done (against the field ) to bring unit positive charge from infinite distance to point in the electric field is called electric potential at that point.
Here, Work done will be more to move B to A rather than P to Q because field is strong(at B to A) therefore more work will to do.
So the potential is different at point A and at point Q?(it is not the same throughout the conductor.)
If i wrong please correct me...