- #1
Alan I
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Homework Statement
Suppose you have two identical droplets of water, each carrying charge 2.8 pC spread uniformly through their volume. The potential on the surface of each is 589 Volts.
Now, you merge the two drops, forming one spherical droplet of water. If no charge is lost, find the potential at the surface of this new large water droplet. in V.
Homework Equations
V = kQ/r
ρ=Q/V
The Attempt at a Solution
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I wasn't sure how to approach this problem so I assumed that the total volume will be conserved (since water is not compressible) and therefore if the volume of one initial droplet doubles after merging (V=2XV0) then the radius will increase by 1/2Xr0.
So by following that reasoning I got rfinal = 6.41 x 10-5 m
⇒ Vfinal = k*Qtotal / rfinal
⇒ Taking the total conserved charge to be Q1 + Q2 ⇒ (2)*(2.8 X 10-12) = 5.6 x 10-12 C
Plugging in all the values I got Vfinal = 785 V , and this result turned out to be wrong
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