- #1
Nikitin
- 735
- 27
hi :)
http://ocw.mit.edu/courses/mechanic...s-fall-2009/course-text/MIT2_017JF09_ch06.pdf
In page 37 they use Newton's 2nd law for a fluid element (while ignoring viscous forces) to derive the bernoulli equation for unsteady flow.
Well, what I am confused about is the last step: They integrate through the x direction, y direction and then z direction to get 3 separate bernoulli equations,,, but then they just add it all up to one? I don't understand the mathematics behind this as I'm completely new to potential theory.
http://ocw.mit.edu/courses/mechanic...s-fall-2009/course-text/MIT2_017JF09_ch06.pdf
In page 37 they use Newton's 2nd law for a fluid element (while ignoring viscous forces) to derive the bernoulli equation for unsteady flow.
Well, what I am confused about is the last step: They integrate through the x direction, y direction and then z direction to get 3 separate bernoulli equations,,, but then they just add it all up to one? I don't understand the mathematics behind this as I'm completely new to potential theory.
Last edited: