- #1
leehufford
- 98
- 1
Homework Statement
A radioactive source is to be used to produce electrical power from the alpha decay of 238 Pu (half life of 88 years).
a) What is the Q value for the decay?
b) Assuming 100% conversion efficiency, how much power could be obtained from the decay of 1.0 g of 238 Pu?
Homework Equations
λ = ln(2)/(88 years)
Number of nuclei = (mass)x(Molar Mass)x(Avogadro's number)
The Attempt at a Solution
I found the correct Q value of 5.594 MeV for part a. But for part b, I found the number of 238 Pu nuclei in a 1.0 g sample to be 1.433x10^26. I reason that there is 5.594 MeV of energy per nuclei, for a total of 8.0165x10^26 MeV total available energy in the sample. The answer is supposed to be in Watts, so I think I need to find the time interval over which the 8x10^26 MeV of energy is released (and convert the MeV to J!). That's why the half life is given, yet I am unsure on how to proceed to getting a time interval. Any help would be greatly appreciated.
-Lee