Power given to particle by centripetal forces

In summary, we are asked to show that the power delivered to a particle of mass m moving in a circular path of constant radius r, with a centripetal acceleration varying with time as a = k2rt2, is equal to mk4r2t5/3. While it may seem confusing that a particle's centripetal acceleration can change with time while still traveling on a circular path of constant radius, this is possible due to the independence of the centripetal and tangential vectors. An example of this concept is seen in the pendulum of a clock, where the velocity and centripetal acceleration change while the radius remains constant.
  • #1
Ghost Repeater
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Homework Statement



A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration a varies with time t as a = k2rt2, where k is a constant. Show that the power delivered to the particle by the forces acting on it is mk4r2t5/3. [/B]

I have solved this problem, but I am still confused about it conceptually. If a particle's centripetal acceleration is changing with time, how can it continue to travel on a circular path of constant radius?
 
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  • #2
Ghost Repeater said:
If a particle's centripetal acceleration is changing with time, how can it continue to travel on a circular path of constant radius?
It can speed up and slow down. I see no language in the problem statement restricting its tangential acceleration.

Clearly, knowing the centripetal acceleration as a function of time gives tangential velocity as a function of time and, accordingly, the tangential acceleration as a function of time.
 
  • #3
It may be moving along a circular track of some sort (think bead on a wire), or perhaps it's fixed to the end of a light rod that pivots about the center. Or, perhaps it is kept on trajectory by tiny rockets :smile:
 
  • #4
Ok, so centripetal and tangential vectors are independent of one another, analogous to the way that horizontal and vertical components of motion are independent in projectile problems?

But in that case how can a centripetal acceleration change the tangential velocity?
 
  • #5
Ghost Repeater said:
Ok, so centripetal and tangential vectors are independent of one another, analogous to the way that horizontal and vertical components of motion are independent in projectile problems?

But in that case how can a centripetal acceleration change the tangential velocity?
There is no reason for it to need to. We are told how the centripetal acceleration changes with time. We are told that the object follows a circular path. We are not told that this causes the tangential acceleration. We merely infer the tangential acceleration because it is required to make the givens of the problem possible.
 
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An example would be the pendulum in a clock. As it swings back and forth the velocity and centripetal acceleration changes but the radius remains constant.
 

Related to Power given to particle by centripetal forces

What is centripetal force?

Centripetal force is the force that acts on an object moving in a circular path, directed towards the center of the circle.

How does centripetal force affect the motion of particles?

Centripetal force causes particles to continuously change direction, keeping them moving in a circular path. It also affects the speed of the particles, as the force must be strong enough to counteract the natural tendency of the particles to move in a straight line.

What is the relationship between centripetal force and power?

The power given to a particle by centripetal force is the rate at which work is done on the particle to keep it moving in a circular path. The greater the centripetal force, the more power is required to maintain the circular motion.

Can centripetal force be converted into other forms of energy?

Yes, centripetal force can be converted into other forms of energy, such as kinetic energy, potential energy, or thermal energy. This depends on the type of motion and the objects involved.

How is centripetal force calculated?

Centripetal force is calculated using the formula F=mv²/r, where F is the force, m is the mass of the particle, v is the velocity of the particle, and r is the radius of the circular path.

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