- #1
lofty28
- 9
- 0
A DC circuit has resistances of 10Ω, 12Ω, and 10Ω respectively. Also has 2 light bulbs with identical tungsten (resistivity = 5.6* 10^-8) filament bulbs with filament thickness of 12um and length of 1.2cm. The source is a 12V.
what is the power loss over the first light bulb?
I am not entirely sure which equations to use how ever the ones which i thought to use are:
V=RI
P=VI
P=V^2 / R
I am really stuck and don't know how to find the acual power loss. I think my main issue is gather the correct information and implimenting it in the right situation.
I have attempted to find the total, R1+R2+R3= 32Ω
And then i have divided each by the source 12... 2.66A
Can someone please direct me in the right way...? I am gettin quiet frustrated with it!
what is the power loss over the first light bulb?
I am not entirely sure which equations to use how ever the ones which i thought to use are:
V=RI
P=VI
P=V^2 / R
I am really stuck and don't know how to find the acual power loss. I think my main issue is gather the correct information and implimenting it in the right situation.
I have attempted to find the total, R1+R2+R3= 32Ω
And then i have divided each by the source 12... 2.66A
Can someone please direct me in the right way...? I am gettin quiet frustrated with it!