- #1
Electro Dave
- 12
- 0
Hi,
I'm trying to figure out the minimum power in watts or HP to move a front wheel drive vehicle that is man-powered with pedals, of a given base weight and then to know how much people would be needed to pedal in order to break inertia and a constant of how much more power is needed for each additional person on board, considering a standard rider's weight and standard rider's power output.
The vehicle has 4 wheels, and only the front wheels are being driven. There is a constant drag from the whole gearing mechanism because the only freewheeling devices are at the pedals, which means the shafts and gearbox will always oppose resistance to the rotation of the front wheel. This will be added as an additional power rating on top of the basic power needed to break inertia.
The vehicle has a plain weight of 1 700lbs, including the driver (driver doesn't power the vehicle, only steers and brake);
Each additional rider weights 180lbs and can output roughly 100lbs/ft of torque up to a 40rpm cadence (0,76hp) and up to 90rpm (1,71hp) for a very short period of time, but still the max torque per rider is 100lbs/ft.
The gear ratio from the crankset to the wheel is about 0,75:1, meaning one full crank rotation will result in 3/4 rotation of the wheel. Friction coefficient is rubber on dry pavement.
A minimum of one rider has to be accounted to break inertia, but I highly doubt that 100lbs/ft of torque can be enough to break inertia of a 1 880lbs vehicle considering a 0,75:1 ratio (133lbs/ft to the wheels) ?
I'd like to know how much torque I would need at least to break inertia and how much power would be needed to maintain momentum, so I can more easily size the gearbox and calculate final gear ratio to reach a good top speed without needing too much torque from the riders to break inertia. We can have up to 12 riders, plus an additional 4 passengers, for a total of 16 plus driver, so a max weight of 4 580lbs and a max torque of 1 200lbs/ft from the riders.
On our current vehicle, we found that only 6 riders are needed to achieve a top speed, even when we are fully loaded at 4 500lbs, meaning they max out at about 120rpm at the crank, giving each a peak of 2hp for a short sprint period. Also, we found that 2 riders could break inertia, but couldn't maintain momentum for more than a very short period of time, because it required too much peak power.
My goal is to define the torque inflicted to the gearbox when breaking inertia and power needed to keep momentum.
I'm trying to figure out the minimum power in watts or HP to move a front wheel drive vehicle that is man-powered with pedals, of a given base weight and then to know how much people would be needed to pedal in order to break inertia and a constant of how much more power is needed for each additional person on board, considering a standard rider's weight and standard rider's power output.
The vehicle has 4 wheels, and only the front wheels are being driven. There is a constant drag from the whole gearing mechanism because the only freewheeling devices are at the pedals, which means the shafts and gearbox will always oppose resistance to the rotation of the front wheel. This will be added as an additional power rating on top of the basic power needed to break inertia.
The vehicle has a plain weight of 1 700lbs, including the driver (driver doesn't power the vehicle, only steers and brake);
Each additional rider weights 180lbs and can output roughly 100lbs/ft of torque up to a 40rpm cadence (0,76hp) and up to 90rpm (1,71hp) for a very short period of time, but still the max torque per rider is 100lbs/ft.
The gear ratio from the crankset to the wheel is about 0,75:1, meaning one full crank rotation will result in 3/4 rotation of the wheel. Friction coefficient is rubber on dry pavement.
A minimum of one rider has to be accounted to break inertia, but I highly doubt that 100lbs/ft of torque can be enough to break inertia of a 1 880lbs vehicle considering a 0,75:1 ratio (133lbs/ft to the wheels) ?
I'd like to know how much torque I would need at least to break inertia and how much power would be needed to maintain momentum, so I can more easily size the gearbox and calculate final gear ratio to reach a good top speed without needing too much torque from the riders to break inertia. We can have up to 12 riders, plus an additional 4 passengers, for a total of 16 plus driver, so a max weight of 4 580lbs and a max torque of 1 200lbs/ft from the riders.
On our current vehicle, we found that only 6 riders are needed to achieve a top speed, even when we are fully loaded at 4 500lbs, meaning they max out at about 120rpm at the crank, giving each a peak of 2hp for a short sprint period. Also, we found that 2 riders could break inertia, but couldn't maintain momentum for more than a very short period of time, because it required too much peak power.
My goal is to define the torque inflicted to the gearbox when breaking inertia and power needed to keep momentum.