Power network short circuit current calc

In summary, the conversation discusses a power network with two parallel generators, two parallel delta-wye transformers, and a bus tie. The transformers feed a bus with multiple 33kV/690V delta-wye transformers for distribution. There was a recent fault at the bus, which was modeled in power network software to determine the peak asymmetrical fault current. The individual also attempted to calculate this by hand and noticed that textbooks often ignore source and line impedance before the distribution transformer. They have their own theories on why this is the case and are seeking clarification. They also mention a related standard, IEC60909, which does not neglect the source impedance in short circuit calculations. The conversation ends with the individual solving their initial problem.
  • #1
lavalin
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I have a power network, two parallel generators which feed 2 parallel delta-wye transformers with a bus tie inbetween, from 690V to 33kV. These two transformers feed a bus which a whole bunch of 33kV/690V DELTA-WYE transformers hang off for distribution.

There was a fault the other day at the bus which is fed from one of these 33kV/690V step down transformers which I modeled in some power network software to determine the peak value of asymmetrical fault current.

I decided to try and compute it by hand (something I have not done in a very long time) just to confirm the result of the simulation. I looked at some textbooks and I noticed all of them ignore source and line impedance (33kV side) before the 33kV/690V distribution transformer and state the current is limitted purely by the 33kV/690V impedance + the bus bar (which it feeds) impedance.

I am no specialist in power protection but I have my own theories why the source impedance can be ignored. Can anyone shed some light on why the textbooks do it?

I also found IEC60909 which does not neglect source impedance when performing a short circuit calc. It is quite confusing as to the way they do it. They seem to reference the impedance on the 33kV side of the transformer to 690V. Can anyone explain how the impedance on the 33kV side is seen from the 690V side?
 
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  • #2
Solved it, thanks.
 

FAQ: Power network short circuit current calc

What is a power network short circuit?

A power network short circuit occurs when there is an unintended connection between two or more points in an electrical circuit, resulting in a sudden increase in current flow. This can cause damage to equipment and pose a safety hazard.

How is short circuit current calculated?

Short circuit current is calculated by determining the impedance of the circuit, which is the total resistance to current flow. This is done by measuring the resistance of all components in the circuit and calculating the total resistance. The short circuit current can then be calculated using Ohm's Law (I = V/R).

Why is it important to calculate short circuit current?

Calculating short circuit current is important for ensuring the safety and reliability of the power network. It helps determine the maximum current that can flow through the system and allows for appropriate protection measures to be implemented to prevent damage and hazards in the event of a short circuit.

What factors can affect short circuit current?

Short circuit current can be affected by a number of factors including the source of the current, the impedance of the circuit, and the presence of protective devices such as fuses and circuit breakers. Additionally, the type and condition of the equipment in the circuit can also impact the short circuit current.

How can short circuit current be managed?

There are several ways to manage short circuit current, including using protective devices such as fuses and circuit breakers, implementing proper grounding and bonding techniques, and reducing the impedance in the circuit. Conducting regular maintenance and inspections can also help identify and address potential issues that may contribute to short circuit currents.

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