Power of a spherical refracting surface

In summary, the power of a spherical refracting surface is given by P = (n2 - n1)/R, where n1 and n2 are the refractive indices of the object and image space, and R is the radius of curvature of the surface. However, when deriving the expression, the wrong value for the focal length (f1) was used, resulting in a different expression. The correct expression is P = n1/f1, where f1 is the focal length in the medium with refractive index n1.
  • #1
Amith2006
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The power of a spherical refracting surface is given as, P = (n2 – n1)/R
Where n1 = refractive index of object space, n2 = refractive index of image space
R = Radius of curvature of the spherical surface
I tried to derive the expression but I got a different expression.
Let u and v be the object and image distance from the spherical surface respectively.
Suppose the spherical refracting surface produces the image of a real object placed at its first principal focus at infinity. Then,
u = +f1, v = infinity
For refraction at a spherical surface,
(n2)/v + (n1)/u = (n2 – n1)/R
(n2)/(infinity) + (n1)/f1 = (n2 – n1)/R
0 + (n1)/f1 = (n2 – n1)/R
f1 = [(n1)(R)]/( (n2 – n1)
Power = 1/f1
Therefore P = (n2 – n1)/[(n1)(R)]
Could you please tell me where I have gone wrong?
 
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  • #2
Amith2006 said:
The power of a spherical refracting surface is given as, P = (n2 – n1)/R
Where n1 = refractive index of object space, n2 = refractive index of image space
R = Radius of curvature of the spherical surface
I tried to derive the expression but I got a different expression.
Let u and v be the object and image distance from the spherical surface respectively.
Suppose the spherical refracting surface produces the image of a real object placed at its first principal focus at infinity. Then,
u = +f1, v = infinity
For refraction at a spherical surface,
(n2)/v + (n1)/u = (n2 – n1)/R
(n2)/(infinity) + (n1)/f1 = (n2 – n1)/R
0 + (n1)/f1 = (n2 – n1)/R
f1 = [(n1)(R)]/( (n2 – n1)
Power = 1/f1
Therefore P = (n2 – n1)/[(n1)(R)]
Could you please tell me where I have gone wrong?
It looks like f1 is the focal length in air (n = 1). The power is the reciprocal of the focal length in the medium. That focal length is f1/n1 in a medium with index of refraction n1. So the power is P = n1/f1

AM
 
  • #3


Your derivation is correct up to the point where you set u = +f1 and v = infinity. This assumption is only valid for a specific case where the object is placed at the first principal focus of the spherical surface and the image is formed at infinity. In general, the object and image distances can vary and the expression for power will be different.

To derive the general expression, we can use the thin lens equation:

1/u + 1/v = (n2 - n1)/R

Rearranging this equation, we get:

1/v = (n2 - n1)/R - 1/u

Substituting this in the power equation, we get:

P = n2/v - n1/u

Since v and u can vary, we cannot simplify this any further. This is the general expression for the power of a spherical refracting surface.
 

FAQ: Power of a spherical refracting surface

What is the power of a spherical refracting surface?

The power of a spherical refracting surface is a measure of its ability to refract or bend light. It is expressed in diopters (D) and is equal to the reciprocal of the focal length of the surface in meters.

How is the power of a spherical refracting surface calculated?

The power of a spherical refracting surface can be calculated by dividing the refractive index of the material by the radius of curvature of the surface. It can also be calculated by multiplying the refractive index by the difference in curvature between the two surfaces of the lens.

What is the significance of the power of a spherical refracting surface?

The power of a spherical refracting surface is an important factor in determining the strength and effectiveness of a lens. It is used to correct vision problems such as nearsightedness, farsightedness, and astigmatism. The higher the power, the stronger the lens and the greater its ability to correct vision.

How does the power of a spherical refracting surface affect the image formed by a lens?

The power of a spherical refracting surface determines the curvature of the lens and therefore, the focal length. A lens with a higher power will have a shorter focal length and will produce a more magnified image. Conversely, a lens with a lower power will have a longer focal length and will produce a less magnified image.

How can the power of a spherical refracting surface be adjusted?

The power of a spherical refracting surface can be adjusted by changing the curvature of the lens. This can be achieved by altering the refractive index of the material or by changing the radius of curvature of the lens. This is often done through the use of different types of lenses, such as convex or concave lenses, or by using corrective eyeglasses or contact lenses.

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