- #1
PsychonautQQ
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Homework Statement
A cavity at Temperature 6000k has an energy distribution corresponding to a blackbody. We make a small hole in it 1mm in diameter.
Calculate the power radiated through the hole of wavelength interval between 550nm and 551nm.
HINT: when dλ is small (such in this case), certain assumptions can be made regarding λ and a product can be used to approximate an integral
2. Cool Equation that's probably useful:
u(λ)= 8*pi*h*c*(λ^-5)*(e^(hc/λkt)-1)^(-1)
λT = 2.898*10^-3 maybe this will be useful? (wiens shiznit)
R=σT^4
The Attempt at a Solution
Hope someone is smart out there :X hah.
Alright so first of all I'm having some conceptual problems with this... the power radiated THROUGH the hole isn't dependent on the overall surface area of the cavity? It seems it's not as it gave us no information about the size or shape of the cavity.. so that's a bit offputting from the start...
So the total power radiated from the cavity is σT^4, because the cavity approximates a blackbody. But how much is radiated through the HOLE at that wavelength? any guidance?