Power Series for f(2x): Exploring the Expansion

In summary, the power series for f(2x) can be expressed as \sum_{n=0}^{\infty}b_n\left(x-\frac a 2\right)^n where b_n=a_n2^n, based on the given power series for f(x).
  • #1
moo5003
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If f(x) has a power series: a_n(x-a)^n (centered at a)

what does the power series for f(2x) look like?
 
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  • #2
moo5003 said:
If f(x) has a power series: a_n(x-a)^n (centered at a)

what does the power series for f(2x) look like?

You have a problem with this? If "f(x) has power series a_n(x-a)^n" (by which I assume you mean
[tex]\Sigma a_n (x-a)^n[/tex]
Doesn't it follow that:
[tex]f(2x)= \Sigma a_n (2x-a)^n[/tex]?
 
  • #3
Hmm..
I would think he is after something like this:
[tex]f(2x)=\sum_{n=0}^{\infty}a_{n}(2x-a)^{n}=\sum_{n=0}^{\infty}{a_{n}}{2^{n}}\sum_{l=0}^{n}\binom{n}{l}(\frac{a}{2})^{n-l}(x-a)^{l}[/tex]
and then reorganize this double sum into some expression:
[tex]f(x)=\sum_{n=0}^{\infty}b_{n}(x-a)^{n}[/tex]
with a known sequence b_n
 
  • #4
I would think he is after something like this:

[tex]f(2x) = \sum_{n=0}^{\infty}a_n(2x-a)^n = \sum_{n=0}^{\infty}a_n2^n\left(x-\frac a 2\right)^n =\sum_{n=0}^{\infty}b_n\left(x-\frac a 2\right)^n[/tex]

where [itex]b_n=a_n2^n[/itex]
 
  • #5
D H said:
I would think he is after something like this:

[tex]f(2x) = \sum_{n=0}^{\infty}a_n(2x-a)^n = \sum_{n=0}^{\infty}a_n2^n\left(x-\frac a 2\right)^n =\sum_{n=0}^{\infty}b_n\left(x-\frac a 2\right)^n[/tex]

where [itex]b_n=a_n2^n[/itex]

You did all the work!

Oh well, I hope he sees how it came around to this.
 

FAQ: Power Series for f(2x): Exploring the Expansion

What is a power series expansion?

A power series expansion is a mathematical concept used to represent a function as an infinite sum of terms, each with a different power of the independent variable. It is often used to approximate functions that are difficult to solve for directly.

How is a power series expansion useful?

A power series expansion allows us to approximate a function at any point by using a finite number of terms from the series. This can be useful in many areas of science, such as physics, engineering, and economics, where complex functions are often encountered.

How is a power series expansion for f(2x) different from a regular power series expansion?

The only difference is that in a power series expansion for f(2x), the independent variable is replaced by 2x in each term. This allows us to find a power series expansion for f(2x) by using the coefficients and exponents from the original power series for f(x).

What are the benefits of using a power series expansion for f(2x)?

Using a power series expansion for f(2x) can simplify calculations and make it easier to approximate the function at different points. It can also help us understand the behavior of the function, such as its rate of change and convergence.

Are there any limitations to using a power series expansion for f(2x)?

Yes, there are some limitations. Power series expansions are only accurate for a certain range of values. Outside of this range, the approximation may not be accurate. Additionally, some functions may not have a power series expansion or may have a very complex one, making it difficult to use in practice.

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