Power series product convergence

  • #1
Hill
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Homework Statement
Give an example of a pair of origin-centered power series, say P(z) and Q(z), such that the disc of convergence for the product P(z)Q(z) is larger than either of the two discs of convergence for P(z) and Q(z).
Relevant Equations
##\frac 1 {1-z} = 1+z+z^2+z^3+\cdots##
I take $$P(z)=\frac {1-z}{5-z} = \frac 1 5 -\frac 4 {25} z - \frac 4 {125} z^2 - \cdots$$ which has radius of convergence 5, and $$Q(z)=\frac {5-z} {1-z} = 5+4z+4z^2+\cdots$$ which has radius of convergence 1.
##P(z)Q(z)=1## converges everywhere.
Is this correct? If so, do you think it's a good example or rather a dirty trick, or both?
 
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  • #2
I think that is a good example.
 
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  • #3
I like it. It's much simpler and more convincing than any examples that I started to think of.
 
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Related to Power series product convergence

1. What is a power series?

A power series is an infinite series of the form ∑(a_n * (x - c)^n), where a_n represents the coefficient of the nth term, x is the variable, and c is the center of the series. It generalizes polynomials to infinite sums and is used to represent functions in a form that can be manipulated algebraically.

2. When does a power series converge?

A power series ∑(a_n * (x - c)^n) converges if there exists a real number R (called the radius of convergence) such that the series converges for all x within the interval |x - c| < R. Outside this interval, the series diverges. At the boundary points |x - c| = R, the series may converge or diverge depending on the specific series.

3. How do you determine the radius of convergence of a power series?

The radius of convergence R of a power series ∑(a_n * (x - c)^n) can be found using the formula R = 1 / lim sup (|a_n|^(1/n)), where lim sup denotes the limit superior. Alternatively, if the limit exists, R can be found using R = 1 / lim (|a_n+1 / a_n|) as n approaches infinity.

4. What is the product of two power series and when does it converge?

The product of two power series ∑(a_n * x^n) and ∑(b_n * x^n) is given by the Cauchy product: ∑(c_n * x^n), where c_n = ∑(a_k * b_(n-k)) for k = 0 to n. The product series converges within the interval where both original series converge, which is typically the minimum of their radii of convergence. However, special care must be taken at the boundaries.

5. Can power series be differentiated and integrated term-by-term?

Yes, within the radius of convergence, a power series can be differentiated and integrated term-by-term. If ∑(a_n * (x - c)^n) converges for |x - c| < R, then its term-by-term differentiated series ∑(n * a_n * (x - c)^(n-1)) and integrated series ∑(a_n * (x - c)^(n+1) / (n+1)) also converge within the same interval.

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