Precession of relativistic orbit in pure inverse-square force

In summary, the conversation discussed how Special Relativity predicts a precession of π(GMm/cl)2 radians per orbit for any elliptic orbit under a pure inverse-square force. To make this relativistic, the equation was modified to include ϒ = 1/√(1 - (v2/c2)), and the resulting precession in radians per orbit was found to be 2π(1/ω - 1) (Eq. 3). However, further calculations using (Eq. 4) did not give the desired result. The individual seeking help is unsure of what they may be doing wrong and is open to any suggestions or rewording of the initial question.
  • #1
RylonMcknz
5
0
PROBLEM:
Show that Special Relativity predicts a precession of π(GMm/cl)2 radians per orbit for any elliptic orbit under a pure inverse-square force.

where G is gravitational constant, M is mass of larger body, m is mass of smaller orbiting body, c is speed of light and l is angular momentum.​

HINTS:
Differential equation for Newtonian inverse-square force orbit: d2u/dθ2 + u = mk/l2 (Eq.1), where u = 1/r, k = GMm.

To make this relativistic: mk→ϒmk, where ϒ = 1/√(1 - (v2/c2)).

Also E = ϒmc2 + U.

Then right side of (Eq. 1) becomes ⇒ϒmk/l2 = (E - U)k/c2l2 = (E + ku)k/c2l2 (Eq. 2).

Precession causes the following change of phase angle (in radians/orbit):

Δθ - Δθ' = 2π/ω - 2π = 2π(1/ω - 1) (Eq. 3).​

ATTEMPT:
(Eq. 1) & (Eq. 2) d2u/dθ2 + u = (E + ku)k/c2l2

d2u/dθ2 + u - k2u/c2l2 =
Ek/c2l2

⇒ d2u/dθ2 + (1 - k2/c2l2)u = Ek/c2l2
,

where ω2 = (1 - k2/c2l2) (Eq. 4),
and let A = Ek/c2l2.

Then substitute y = u - A/ω2.

Then we have d2y/dθ2 + ω2[y + A/ω2] - A = 0

d2y/dθ2 + ω2y = 0

Solution is then y = y0cos(ωθ - θ0).

I then try substituting (Eq. 4) into (Eq. 3) to find the resulting precession in radians per orbit, but this doesn't not give the desired result. This is where I'm stuck, not sure what I'm doing wrong. Thank you for your considerations.​




 
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  • #2
Thanks for the post! Sorry you aren't generating responses at the moment. Do you have any further information, come to any new conclusions or is it possible to reword the post?
 

Related to Precession of relativistic orbit in pure inverse-square force

1. What is the precession of relativistic orbit in pure inverse-square force?

The precession of relativistic orbit in pure inverse-square force refers to the gradual change in the orientation of an orbit over time due to the influence of an inverse-square force, which is a type of force that decreases in strength with the square of the distance between two objects.

2. What is the cause of the precession of relativistic orbit in pure inverse-square force?

The cause of the precession of relativistic orbit in pure inverse-square force is the combination of the gravitational force between two objects and the relativistic effects of space and time.

3. How is the precession of relativistic orbit in pure inverse-square force calculated?

The precession of relativistic orbit in pure inverse-square force is calculated using complex mathematical equations, such as the Schwarzschild solution, which takes into account the effects of general relativity. It also depends on the masses and distances of the objects involved.

4. Can the precession of relativistic orbit in pure inverse-square force be observed in real life?

Yes, the precession of relativistic orbit in pure inverse-square force has been observed in many real-life scenarios, such as the orbit of Mercury around the Sun and the orbit of binary stars. It is a well-established phenomenon in astrophysics.

5. How does the precession of relativistic orbit in pure inverse-square force affect the stability of orbits?

The precession of relativistic orbit in pure inverse-square force can lead to changes in the shape and orientation of an orbit, potentially causing it to become unstable over time. This effect must be taken into consideration in the study and prediction of celestial orbits.

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