Preciptation(Molecular Equation and net ionic equation)

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In summary, the molecular equation for reaction A is Na2CO3 + MgBr2 ---> 2NaBr + MgCO3. The net ionic equation is 2Na+(aq) + CO3^2-(aq) + Mg^2+(aq) + 2Br-(aq) --> 2Na+(aq) + 2Br-(aq) + MgCO3(s). For reaction B, the molecular equation is MgSO4 + 2NaOH ---> Mg(OH)2 + Na2SO4. The net ionic equation is Mg^2+(aq) + SO4^2-(aq) + 2Na+(aq) + 2OH-(aq) --> Mg(OH)
  • #1
Susanem7389
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Write the molecular eqaution and the net ionic equation for each of the following aqueous reactions. If no reaction occurs, write NR after the arrow.

A) Na2Co3 + MgBr2--->
B)MgSO4 + NaOH---->

I can't figure these two out. From the solubility rules, all the compounds are soluble so there shouldn't be a reation but the answer in the back of the book shows a reaction.

What am I doing wrong?
 
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  • #2
Solubility is not 0/1 - substance is either soluble or insoluble. All salts are soluble, just some more and some less. Depending on where do you put the border between those that will be classified as soluble and insoluble rules will be slightly different.

However, there are two weakly soluble products of these reactions - two that I beleve should be listed in most solubility rules tables.
 
  • #3


Molecular equation for A: Na2CO3 + MgBr2 --> 2NaBr + MgCO3

Net ionic equation for A: 2Na+ + CO3^2- + Mg2+ + 2Br- --> 2Na+ + 2Br- + MgCO3 (s)

Molecular equation for B: MgSO4 + 2NaOH --> Mg(OH)2 + Na2SO4

Net ionic equation for B: Mg2+ + SO4^2- + 2Na+ + 2OH- --> Mg(OH)2 (s) + 2Na+ + SO4^2-

Based on the solubility rules, both of these reactions should not occur because all of the compounds are soluble. However, it is possible that the reaction in the book is a precipitation reaction that is not accounted for by the solubility rules. It is also possible that there is a typo in the book. I would recommend double checking the information and possibly consulting with a chemistry colleague or instructor for clarification.
 

FAQ: Preciptation(Molecular Equation and net ionic equation)

1. What is precipitation in a molecular equation?

Precipitation in a molecular equation refers to the formation of a solid substance when two aqueous solutions are combined. This solid is known as a precipitate and is formed when the product of the reaction is insoluble in water.

2. How is a net ionic equation different from a molecular equation?

A net ionic equation is a simplified version of a molecular equation that only includes the species that are actually involved in the reaction. This means that any spectator ions, which do not participate in the reaction, are eliminated from the equation.

3. What is the purpose of writing a net ionic equation?

The purpose of writing a net ionic equation is to focus on the essential components of a chemical reaction and eliminate any irrelevant information. This makes it easier to understand the reaction and determine the actual products that are formed.

4. How do you balance a precipitation reaction?

To balance a precipitation reaction, you must first write out the correct molecular equation and then balance the number of atoms on each side of the equation by adding coefficients. It is important to remember that coefficients can only be added in front of compounds, not individual atoms.

5. Can a precipitate be formed in a single displacement reaction?

Yes, a precipitate can be formed in a single displacement reaction. This occurs when a more reactive metal replaces a less reactive metal in a compound, causing the formation of a solid precipitate. This type of reaction is known as a single displacement or replacement reaction.

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