Pressure equation of sound wave

In summary, the conversation discusses the derivation of the pressure equation for a sound wave using the bulk modulus, B, and the change in volume, \DeltaV. The person is struggling to determine the correct expression for \DeltaV, which can either be S.y or S\Deltay. The first expression would represent the difference in pressure between the initial and final volume of the air column, while the second expression would represent the change in pressure for a change in the length of the column. The person is seeking clarification on which expression to use for the pressure equation of the sound wave.
  • #1
abhineetK
18
0
Let us consider sound (longitudinal) wave
y=A.sin([tex]\omega[/tex]t-kx)

See attachment for diagram

Consider air column of length [tex]\Delta[/tex]x and cross-sectional area S at distance x from source.
I want to derive the pressure equation of the sound wave using
Bulk modulus, B=-[tex]\Delta[/tex]P/([tex]\Delta[/tex]V/V)
implying [tex]\Delta[/tex]P=-B.[tex]\Delta[/tex]V/V

But the trouble is that I am not able to select the expression for [tex]\Delta[/tex]V
1) [tex]\Delta[/tex]V=S.y
2) [tex]\Delta[/tex]V=S[tex]\Delta[/tex]y
TELL ME WHICH EXPRESSION OUT OF THE TWO SHOULD I USE with EXPLANATION.
 

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  • #2
I give you a hint about what I was actually thinking.

1)[tex]\Delta[/tex]V=S.y
It would mean that [tex]\Delta[/tex]P is the difference between the initial pressure of the volume considered and the final pressure of the same column (now volume is reduced to (V-[tex]\Delta[/tex]V) but mass(amount) remains same).

2)[tex]\Delta[/tex]V=S.[tex]\Delta[/tex]y
It would mean that [tex]\Delta[/tex]P is the change in pressure for a change [tex]\Delta[/tex]y
in the length of the column.

Which of the above does the pressure equation of sound wave denotes? Please, tell.

NOTE: If you find any problem in understanding what I want to say, please tell.
 
  • #3


The correct expression to use for \DeltaV is \DeltaV = S\Deltay, where \Deltay is the change in displacement of the air particles. This is because the change in volume of the air column is directly proportional to the change in displacement of the air particles. When a sound wave travels through a medium, it causes the air particles to vibrate back and forth in the direction of the wave's propagation. This vibration leads to a change in the volume of the air column, which can be represented by \DeltaV.

Using this expression for \DeltaV in the bulk modulus equation, we can derive the pressure equation of the sound wave as follows:

B = -\DeltaP/(\DeltaV/V) [Definition of bulk modulus]
B = -\DeltaP/(S\Deltay/V) [Substituting \DeltaV = S\Deltay]
B = -\DeltaP/(\Deltay/V) [S cancels out]
B = -V\DeltaP/\Deltay [Multiplying both sides by V]
V\DeltaP = B\Deltay [Rearranging terms]
\DeltaP = B\Deltay/V [Dividing both sides by V]

This is the pressure equation of the sound wave, which shows that the pressure change (\DeltaP) is directly proportional to the change in displacement of the air particles (\Deltay). It also shows that the bulk modulus (B) of the medium plays a role in determining the magnitude of the pressure change.

In summary, the expression \DeltaV = S\Deltay should be used because it accurately represents the relationship between the change in volume of the air column and the change in displacement of the air particles, in the context of a sound wave.
 

FAQ: Pressure equation of sound wave

What is the pressure equation of a sound wave?

The pressure equation of a sound wave is described by the formula P = ρc², where P is the sound wave pressure, ρ is the density of the medium, and c is the speed of sound in that medium.

How is pressure related to the amplitude of a sound wave?

The pressure of a sound wave is directly proportional to its amplitude. This means that as the amplitude increases, the pressure of the sound wave also increases.

What happens to the pressure of a sound wave when it travels through different media?

The pressure of a sound wave changes as it travels through different media. This is because the density and speed of sound in the medium affect the pressure equation of the sound wave.

How does the pressure of a sound wave change with distance?

The pressure of a sound wave decreases as it travels further away from its source. This is due to the spreading out of the sound wave and the dissipation of its energy over distance.

Can the pressure equation of a sound wave be used to calculate the loudness of a sound?

No, the pressure equation of a sound wave only describes the physical properties of the wave. Loudness is a subjective perception that is influenced by factors such as the sensitivity of the human ear and the surroundings in which the sound is heard.

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