Pressure inside a sealed container

In summary, pressure inside a sealed container is determined by the amount of gas molecules, the temperature, and the volume of the container. As the number of gas molecules increases or the temperature rises, the pressure also increases due to more frequent and forceful collisions with the container walls. Conversely, increasing the volume of the container leads to a decrease in pressure, as molecules have more space to move and collide less frequently. This relationship is described by the ideal gas law, which provides a fundamental understanding of gas behavior in closed systems.
  • #1
brochesspro
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Homework Statement
A cylindrical vessel of height 500 mm has an orifice (small hole) at its bottom. The orifice is initially closed and water is filled in it up to height H. Now the top is completely sealed with a cap and the orifice at the bottom is opened. Some water comes out from the orifice and the water level in the vessel becomes steady with height of water column being 200 mm. Find the fall in height (in mm) of water level due to opening of the orifice.
Relevant Equations
Theoretical doubt.
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I do know how to solve this question:
We find the equilibrium pressure due to air molecules inside the container (after water has stopped flowing). Then, assuming initial pressure of gas inside the container to be atmospheric pressure, we use Boyle's law to find the new volume of the gas and then after a bit of manipulation we find the depression in water level to be about 6 mm.
Now, my doubt is, how can we take the initial pressure of he gas to be 1 atm after we seal the container? Should the pressure not decrease since the no. of air molecules inside the container decreases?
 
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  • #2
brochesspro said:
Now, my doubt is, how can we take the initial pressure of he gas to be 1 atm after we seal the container? Should the pressure not decrease since the no. of air molecules inside the container decreases?
The gas pressure before the container is sealed is 1 atm because it is in direct contact with the atmosphere. Why would sealing the container change the number of molecules inside it?
 
  • #3
Orodruin said:
Why would sealing the container change the number of molecules inside it?
I meant the no. of molecules that can apply the pressure on the surface of the water, sorry for the poor wording. Initially, all the air above the water surface will apply 1 atm on it. But after the container is sealed, the air molecules above the seal do not apply any pressure on the water, right? Only the molecules inside the container will exert any pressure, so why is the pressure still 1 atm?
 
  • #4
brochesspro said:
I meant the no. of molecules that can apply the pressure on the surface of the water, sorry for the poor wording.
That’s not what gives pressure. What gives pressure is number of molecules per volume.

Think of pressure as the molecules bouncing off the surface. If there are the same number of molecules in a larger volume, fewer will bounce on the surface every unit time, therefore less pressure. The ideal gas law is pV = RNT so ##p \propto N/V##.

brochesspro said:
the air molecules above the seal do not apply any pressure on the water, right?
The sealing procedure does not change N/V.
 
  • #5
To add to that: Without the seal there is of course the atmosphere outside applying pressure to the gas inside the cylinder. If it were not for this pressure the air would simply escape. When you seal the container this pressure is exchanged for a pressure from the seal. The pressure inside the cylinder remains the same (until you open the orifice).
 
  • #6
Orodruin said:
When you seal the container this pressure is exchanged for a pressure from the seal.
Can we instead say that the atmosphere applies a pressure through the seal? And, is the same thing applicable in this question?
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After we seal the tube, the tube, the pressure above the mercury due to the gas is 1 atm cuz the concentration of gas remains the same and we do the same steps as in the previous question, Boyle's law and all.
 
  • #7
brochesspro said:
Can we instead say that the atmosphere applies a pressure through the seal?
No. If this were the case the pressure in the container could never be less than on the outside.
brochesspro said:
And, is the same thing applicable in this question?
Yes.
 
  • #8
Orodruin said:
No. If this were the case the pressure in the container could never be less than on the outside.
Then what does the pressure from the seal mean?
 
  • #9
The seal just removes the contact between the gas in the container and the outside atmosphere. It does not change the pressure of the gas in the container, which is now pressing on the seal rather than the outside atmosphere. Do you think that you always need to have a column of gas to cause of pressure to be present, and without gravity, you can't have pressure?
 
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  • #10
brochesspro said:
Can we instead say that the atmosphere applies a pressure through the seal? And, is the same thing applicable in this question?

After we seal the tube, the tube, the pressure above the mercury due to the gas is 1 atm cuz the concentration of gas remains the same and we do the same steps as in the previous question, Boyle's law and all.
Rather than water or mercury, just imagine an initially supported piston of mass m inside a vertical cylinder.
Pressure of air above and below the faces of the mechanically supported piston in place (unable to fall due to its own weight) are initially equal (the atmosphere reaches the piston both ways).

Then, we solidly close the top open face of the cylinder, and remove the support of the piston.
The piston will then tend to descend under the force equal to mg.
As that happens, the pressure on the bottom face of the piston remains the same atmospheric one.

Nevertheless, the descending movement of the piston makes the volume of that top sealed chamber (fixed number of molecules of air) increase, which induces lower pressure acting on the top face of the piston (increased area inside the chamber against which that fixed number of molecules of air collide).

The weight of our piston is the only thing compensating for that difference of pressures acting on top and bottom equal surfaces of our piston, which should stop its descending trajectory at a unique height of balance.

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FAQ: Pressure inside a sealed container

What factors affect the pressure inside a sealed container?

The pressure inside a sealed container is primarily affected by the temperature, the volume of the container, and the amount of gas inside. According to the ideal gas law (PV=nRT), pressure (P) is directly proportional to the temperature (T) and the amount of gas (n), and inversely proportional to the volume (V) of the container.

How does temperature change impact the pressure inside a sealed container?

When the temperature inside a sealed container increases, the kinetic energy of the gas molecules also increases, causing them to collide more frequently and with greater force against the walls of the container. This results in an increase in pressure. Conversely, a decrease in temperature will result in a decrease in pressure.

What happens to the pressure if the volume of the container is reduced?

If the volume of the container is reduced while keeping the amount of gas and temperature constant, the pressure inside the container will increase. This is described by Boyle's Law, which states that pressure is inversely proportional to volume (P ∝ 1/V) for a given amount of gas at constant temperature.

Can the pressure inside a sealed container reach a point where the container bursts?

Yes, if the pressure inside a sealed container exceeds the structural limits of the container, it can cause the container to burst. This typically happens if the temperature is increased significantly or if additional gas is introduced into the container, raising the internal pressure beyond the container's capacity to withstand it.

How can you calculate the pressure inside a sealed container?

The pressure inside a sealed container can be calculated using the ideal gas law equation: PV = nRT. Here, P is the pressure, V is the volume of the container, n is the number of moles of gas, R is the universal gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin. By rearranging the equation, you can solve for the pressure: P = (nRT)/V.

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