Pressure-Volume PV=C Air & Water in sealed vessel.

In summary, the student is trying to solve a problem involving the pressure of air and water in a tank. They are using information from parts (ii) and (iii). They are trying to find the new height of the water and the volume of water and air in the tank. They are using the pressure of the air and the height of the water to determine the volume of air in the tank. They are trying to find the equation to solve for the pressure of the air and the water at the bottom of the tank.
  • #1
Gorz
29
0

Homework Statement


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Homework Equations



I cannot work out the last part (iii) All other parts have been solved.

The Attempt at a Solution


From part (ii) I found the new height of the water, and therefore the volume of water and air in the vessel. The Pressure of the water P1 can't be found using; rho.g.h+Patmos(for the water) and you know that P2 of the water is going to be Patmos.

Because you have 2 unknowns for the air, surely you must use V2=(P1V1/P2) However, this yields a greater volume that started with, indicating that the height has increase, not gone done, which is what does happen.

Bet its a really simple solution, but I've been on it for about 3 hours.

Cheers.
 
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  • #2
Sunday Morning Bump.
 
  • #3
Hi Gorz. Yes, you have 2 unknowns for the air. But the pressure of the air is related to the height of the column of water. Note that the pressure at the bottom of the tank for iii is atmospheric pressure, so the air pressure is going to be less than atmospheric. Air pressure will be less than atm by rho*g*h. Note that water height also provides a function for the volume of air since the total volume of the tank is simply the summation of the water volume plus the air volume. Does that help?
 
  • #4
Im still baffled by this. I understand the concept of the Air being a vacuum pressure and that you would find it using Patmos-rho.g.h, its getting the height that I can't do. I am not sure what you meen about the height providing a function for the volume.

Ive tried rearranging the V=phiD^2.h/4 and subbing it into the PV=C equation, but I've got nowhere with that.
 
  • #5
Hi Gorz. I don't have much time right now, but see if this helps. Rather than trying to derive the equation directly, sometimes it helps to do a calculation with actual values to see how you might go about determining the equation you need to derive.

Pick an actual value for H at random (let's say 1 meter) and using this value determine:
- The volume of air in the tank.
- The pressure of the air.
- The pressure at the bottom of the tank where the hole is.

Examine how you came up with the pressure of the air and water at the bottom and see if you can then go back and generalize the equations using variables. Hopefully once you do that, it will become obvious how to derive the equation you need.
 

FAQ: Pressure-Volume PV=C Air & Water in sealed vessel.

How does pressure affect the volume of air and water in a sealed vessel?

According to Boyle's Law, the pressure and volume of a gas are inversely proportional. This means that as the pressure on a gas increases, its volume decreases. Therefore, in a sealed vessel, as the pressure increases, the volume of both air and water will decrease.

What is the relationship between pressure and volume in a sealed vessel?

The relationship between pressure and volume in a sealed vessel can be described by the equation PV=C, where P is the pressure, V is the volume, and C is a constant. This equation represents Boyle's Law and shows that as pressure increases, volume decreases, and vice versa.

How do factors such as temperature and gas type affect pressure and volume in a sealed vessel?

Temperature and gas type can affect the pressure and volume in a sealed vessel. For example, increasing the temperature of a gas will increase its volume, while decreasing the temperature will decrease its volume. Additionally, different gases have different properties that can affect their behavior in a sealed vessel.

What happens to the pressure and volume of air and water in a sealed vessel when the vessel is compressed or expanded?

When a sealed vessel is compressed, the pressure on the air and water inside will increase, causing their volumes to decrease. Conversely, when the vessel is expanded, the pressure on the air and water will decrease, causing their volumes to increase.

How is the pressure and volume of air and water in a sealed vessel related to the amount of gas present?

The pressure and volume of air and water in a sealed vessel are directly proportional to the amount of gas present. This means that as the amount of gas increases, the pressure and volume will also increase, and vice versa.

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