desmond iking said:Homework Statement
A committee of 5 members is formed from 6 parents , 2 teachers, and a principal, In how many ways, can this committee be formed if the committee consists of not more than 4 parents?
my working is 1 parent + 2 parents + 3 parents +4 parents
which is (6C1 x 8C4) + (6C2 x 7C3) +(6C3x 6C2)+ (6C4 x 5C1)
but the ans given is only 120
Homework Equations
The Attempt at a Solution
LCKurtz said:Since there are only 3 non-parents your choices for number of parents are 2,3, and 4. Once you have counted the parents, the others must be chosen from the non-parents. Try again.
The probability of having two parents in a committee would depend on the size of the committee and the total number of parents available. If the committee is small and there are a large number of parents, then the probability would be higher. However, if the committee is large and there are only a few parents, the probability would be lower.
The probability of having a certain number of parents in a committee would decrease as the committee size increases. This is because there are more possible combinations of parents that could be chosen, making it less likely for a specific number of parents to be selected.
Yes, the probability can be calculated by dividing the number of possible ways to choose a certain number of parents by the total number of ways to choose any number of parents for the committee. This can be represented as a fraction or decimal.
The probability of having a certain number of parents in a committee would increase as the total number of parents available increases. This is because there are more parents to choose from, making it more likely for a specific number of parents to be selected.
Yes, the probability can be affected by other factors such as the selection process or any criteria for choosing parents for the committee. The probability can also be affected by the number of parents who are willing and available to serve on the committee.