Probability density expected values

In summary, the probability density expected value is a statistical measure used to calculate the average value of a random variable based on its probability density function. It is calculated by multiplying each possible outcome by its probability of occurring and summing these values. This concept is significant in measuring central tendency and is related to variance. The probability density expected value can be negative or zero, depending on the distribution of the random variable.
  • #1
afireinside
3
0

Homework Statement


Bearing capacity of soil varies between 6 and 15 kips/sq.ft. If probability density within this range is given as
f(x)=1/2.7 * (1- x/15), 6 ≤ u ≤ 15
=0 otherwise

Find E(X) and E(X^2)

Homework Equations


E(x) should be ∫x*f(x) dx
E(x^2) should be ∫x^2*f(x) dx


The Attempt at a Solution



E(x) ends up being 9 when I plug it in, but the answer sheet says either 9.55 or 9 * 55 (his decimals can look like multiplication dots)

E(x^2) ends up being 85.5, but the answer sheet says either 230.81 or 230 * 81.

I feel like it should be the * ones, because 9 and 81 are part of them, but I have no clue why, unless my equations are wrong.
 
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  • #2
f(x)=1/2.7 * (1- x/15), 6 ≤ u ≤ 15
... what is "u" in there?
Do you mean:
$$f(x)=\frac{1}{2.7}\left (1-\frac{x}{15}\right )\; :\; 6\leq x \leq 16$$... then
$$E[X]=\frac{1}{243}\int_6^{15} (90x-6x^2)dx$$... sure enough - unless this is something funny in the course.

Probably you've just made a mistake someplace - or the answer sheet could be wrong.
Double check.
 
  • #3
Simon Bridge said:
... what is "u" in there?
Do you mean:
$$f(x)=\frac{1}{2.7}\left (1-\frac{x}{15}\right )\; :\; 6\leq x \leq 16$$... then
$$E[X]=\frac{1}{243}\int_6^{15} (90x-6x^2)dx$$... sure enough - unless this is something funny in the course.

Probably you've just made a mistake someplace - or the answer sheet could be wrong.
Double check.

So are you saying the answer should be 9, and the answer sheet is wrong? Then what about E[x^2], is that 81 or is it 85.5 by doing a similar integral just with x^2 instead of x?
 
  • #4
afireinside said:
So are you saying the answer should be 9, and the answer sheet is wrong? Then what about E[x^2], is that 81 or is it 85.5 by doing a similar integral just with x^2 instead of x?

I get EX = 9 and EX^2 = 85.5.
 
  • #5
Either the question is not what we think it is or the answer sheet is wrong.
I don't want to be definitive about this because I am not there and not the one doing the course.
You should check with someone else doing the course and ask the person who made the answer sheet.
 

FAQ: Probability density expected values

What is probability density expected value?

The probability density expected value is a statistical measure used to calculate the average value of a random variable based on its probability density function. It represents the weighted average of all possible outcomes, with each outcome being weighted by its probability of occurring.

How is probability density expected value calculated?

The probability density expected value is calculated by multiplying each possible outcome of a random variable by its probability of occurring, and then summing all of these values together. This can be represented mathematically as E(X) = ∫ x * f(x) dx, where E(X) is the expected value, x is the random variable, and f(x) is the probability density function.

What is the significance of probability density expected value?

The probability density expected value is an important concept in statistics as it provides a way to measure the central tendency or average value of a random variable. It is also used in various statistical models and calculations, such as in hypothesis testing and decision making.

How is probability density expected value related to variance?

The variance of a random variable is a measure of its spread or variability. It is calculated by taking the sum of squared differences between each possible outcome and the expected value, weighted by their probabilities. Therefore, the probability density expected value is a crucial component in calculating variance.

Can probability density expected value be negative?

Yes, the probability density expected value can be negative if the random variable has a probability density function that takes on negative values. However, this is not always the case and depends on the specific distribution of the random variable. In some cases, the probability density expected value may also be zero.

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