- #1
purplebird
- 18
- 0
given that x has an exponential density function ie p(x) = exp (-x) and x(n) & x(m) are statistically independent.
Now y(n) = x(n-1)+x(n)
what is the pdf (probability density function) of y(n)
Now y(n) = x(n-1)+x(n)
what is the pdf (probability density function) of y(n)