Probability of 3rd drawing is red?

Note: if you are going to have 7 balls in a box, it is customary to have a ball in each of 7 boxes.In summary, the probability of the p-th drawing being red is x/7, where x represents the number of red balls in the box. This probability depends on whether the drawing is done with or without replacement, and the a-priori probability without that information is still x/7. It is customary to have one ball in each of the seven boxes when working with a box containing seven balls.
  • #1
Cylab
54
0
There are 7 balls in box--red and white.
What is probability of p-th drawing is red?
{p=1,...7}

Condition:return of previous drawing and not
returning of previous drawing.

Please help me these two conditions please
Thanks in advance
 
Last edited:
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  • #2
You are the same person who did the "10 boys and girls in line"?

The same thing happens here- if x of the seven balls is red and the drawing of samples is "with replacement", then the probability any one draw is red is x/7. If the drawing is "without replacement" then the probability depends on the previous history. The "a-priori" probability without that information is still x/7.
 

FAQ: Probability of 3rd drawing is red?

What is the probability of the 3rd drawing being red?

The probability of the 3rd drawing being red depends on several factors, such as the total number of objects in the pool, the number of red objects in the pool, and whether the previous drawings have affected the distribution of red objects. Without this information, it is impossible to accurately determine the probability.

Why is the probability of the 3rd drawing being red different from the first two drawings?

The probability of the 3rd drawing being red can differ from the first two drawings due to factors such as the number of red objects in the pool changing after the previous drawings, or the previous drawings influencing the distribution of red objects in the pool.

Can the probability of the 3rd drawing being red be calculated based on the probabilities of the first two drawings?

No, the probability of the 3rd drawing being red cannot be accurately calculated based on the probabilities of the first two drawings. This is because the probabilities of the first two drawings do not account for any changes in the distribution of red objects in the pool or any other factors that may affect the probability.

How can the probability of the 3rd drawing being red be influenced by previous drawings?

The probability of the 3rd drawing being red can be influenced by previous drawings if the previous drawings have affected the distribution of red objects in the pool. For example, if the first two drawings resulted in a high number of red objects being removed from the pool, the probability of the 3rd drawing being red may decrease.

Is there a way to increase the probability of the 3rd drawing being red?

The probability of the 3rd drawing being red can be increased by increasing the number of red objects in the pool or by ensuring that the previous drawings do not significantly alter the distribution of red objects. However, this also depends on the total number of objects in the pool and the specific probabilities of each drawing. In some cases, the probability may not be able to be increased at all.

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