Probability: Poisson distribution involving customer arrivals

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The discussion focuses on calculating probabilities related to customer arrivals at two stores, A and B, modeled by a Poisson distribution with parameter λ. For Question 1, the initial proposed solution was incorrect, but it was later clarified that the correct approach involves summing probabilities for customers in store A while ensuring store B has none. Question 2's solution, which calculates the probability of exactly two customers in store A and none in store B, was confirmed as correct. The conversation also touches on finding a concise form for the summation in Question 1. Overall, the thread emphasizes understanding the application of the Poisson distribution in this context.
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Homework Statement



There are two stores A and B.

Customers can equally enter one of the two stores, i.e., for a specific customer, the probabilities she enters store A or B both are 0.5.

If the total number of customers in two stores has the Poisson distribution of parameter λ, then

Question 1: What is the probability that the number of customers in store A is non-zero and store B has no customers;

Question 2: What is the probability that the number of customers in store A is exactly 2 and store B has no customers.

Homework Equations



Poisson distribution: p(x)=λx/x! * e

The Attempt at a Solution



Answer 1: (1-p(0))*(0.5+0.52+0.53+...)=1-e
Comment: The probability that there are some customer in some store is 1 - p(0), then the probability that x customers entered store A is 0.5x, hence their product should yield the desired answer?

Answer 2: p(2)*0.52
Comment: Similar strategy as answer 1.

Are these correct?

Thank you in advance!
 
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sanctifier said:

Homework Statement



There are two stores A and B.

Customers can equally enter one of the two stores, i.e., for a specific customer, the probabilities she enters store A or B both are 0.5.

If the total number of customers in two stores has the Poisson distribution of parameter λ, then

Question 1: What is the probability that the number of customers in store A is non-zero and store B has no customers;

Question 2: What is the probability that the number of customers in store A is exactly 2 and store B has no customers.


Homework Equations



Poisson distribution: p(x)=λx/x! * e

The Attempt at a Solution



Answer 1: (1-p(0))*(0.5+0.52+0.53+...)=1-e
Comment: The probability that there are some customer in some store is 1 - p(0), then the probability that x customers entered store A is 0.5x, hence their product should yield the desired answer?

Answer 2: p(2)*0.52
Comment: Similar strategy as answer 1.

Are these correct?

Thank you in advance!

You answer to (2) is correct, but your answer to (1) is not.
 
Ray Vickson, thank you for your replay.

If answer (2) is correct, then answer (1) is p(1)*0.5 + p(2)*0.52 + p(3)*0.53 + ...

Is this correct?

If it is, then is there a concise form of the summation?
 
sanctifier said:
Ray Vickson, thank you for your replay.

If answer (2) is correct, then answer (1) is p(1)*0.5 + p(2)*0.52 + p(3)*0.53 + ...

Is this correct?

If it is, then is there a concise form of the summation?

Yes, and yes. For the latter, see https://www.efunda.com/math/exp_log/series_exp.cfm .
 
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