Probability Problems: P(X≤15)=0.3, P(15<X≤24)=0.6, P(X>20)=0.5

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Let P(X\leq \15)= 0.3, P(15\less X \leq24)=6 and (P X > 20) = 0.5I don't understand how I would find this probability: P(15\lessX\leq20

The answer is 0.2.
 
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Are you sure you posted the problem correctly? The probability of an event cannot equal 6, first of all.
 
You are correct, the problem is not posted correctly. My latex coding is lacking...I wish there were a way a could delete this post.
 
Is it meant to be 0.6 by any chance? Thus, is your first equation meant to be P(X\leq \15)= 0.3,\ \ P(15&lt; X \leq24)=0.6,\ \ P(X&gt;20)=0.5, and you want to find P(15&lt; X \leq20)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply . Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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