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travis0868
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This question is from Parzen (Modern Probability Theory), chapter 2, exercise 6.1
Suppose that we have M urns, numbered 1 to M and M balls, numbered 1 to M. Let the balls be inserted randomly in the urns, with one ball in each urn. If a ball is put into the urn bearing the same number as the ball, a match is said to have occurred. Show that for j = 1,...,M the conditional probability of a match in the jth urn, given that there are m matches is m/M.
Probability that there are exactly m matches in M urns is:
(1/m!)* [tex]\Sigma[/tex][tex]^{M-m}_{k=0}[/tex](-1)^k * (1/k!)
The answer doesn't make sense. Suppose that j = M. The probability that there will be a match in the Mth urn given that there are M-1 matches is 1. Not (M-1)/M.
Homework Statement
Suppose that we have M urns, numbered 1 to M and M balls, numbered 1 to M. Let the balls be inserted randomly in the urns, with one ball in each urn. If a ball is put into the urn bearing the same number as the ball, a match is said to have occurred. Show that for j = 1,...,M the conditional probability of a match in the jth urn, given that there are m matches is m/M.
Homework Equations
Probability that there are exactly m matches in M urns is:
(1/m!)* [tex]\Sigma[/tex][tex]^{M-m}_{k=0}[/tex](-1)^k * (1/k!)
The Attempt at a Solution
The answer doesn't make sense. Suppose that j = M. The probability that there will be a match in the Mth urn given that there are M-1 matches is 1. Not (M-1)/M.