- #1
IceXaos
- 8
- 0
The easiest way I can explain this is russian roulette. You have a six-sided die, and I need to find out the probability of the other person rolling a 6 before me, or dying in russian roulette with a 6-chamber revolver.
I know it's different depending on who goes first, so for my example, I went first. This is what I came up with.
Total[(5/6)^x×1/6 where x = {1, 3, 5}]
This gives me the sum of the probability of winning on the first, second, and third round. The problem is, I want the overall probability of winning. The number of rounds may vary by a lot. You could roll a 6 on the first roll, or you may have 20 rounds before either of you roll it.
I just don't understand how I would come up with an answer to this.
Any help is appreciated.
I know it's different depending on who goes first, so for my example, I went first. This is what I came up with.
Total[(5/6)^x×1/6 where x = {1, 3, 5}]
This gives me the sum of the probability of winning on the first, second, and third round. The problem is, I want the overall probability of winning. The number of rounds may vary by a lot. You could roll a 6 on the first roll, or you may have 20 rounds before either of you roll it.
I just don't understand how I would come up with an answer to this.
Any help is appreciated.