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stylez03
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Homework Statement
To study the structure of the lead nucleus, electrons are fired at a lead target. Some of the electrons actually enter the nuclei of the target, and the deflection of these electrons is measured. The deflection is caused by the charge of the nucleus, which is distributed approximately uniformly over the spherical volume of the nucleus. A lead nucleus has a charge of + 82e and a radius of R = 7.10×10^−15
Find the acceleration of an electron at a distance of 3.00 R from the center of a lead nucleus.
Homework Equations
Charge of Electron = -1.60*10^-19
Mass of Electron = 9.11*10^-31
[tex] F = \frac {k*q*Q} {r^{2}} [/tex]
[tex] k = \frac {1} {4*pi*e_o} [/tex]
[tex] e_o = 8.85*10^{-12} [/tex]
[tex] A = \frac {F} {m} [/tex]
The Attempt at a Solution
=> [tex] F = \frac {\frac {1} {4*pi*8.85*10^{-12}}*-1.60*10^{-19}*82*1.60*10^{-19}} {(3*(7.10*10^{-15})^{2}} [/tex]
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