- #1
Chasing_Time
- 8
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Hi all, I am getting stuck on this problem from chapter 4 of Fermi's Thermodynamics:
"A body obeys the equation of state:
pV[tex]^{1.2}[/tex] = 10[tex]^{9}[/tex]T[tex]^{1.1}[/tex]
A measurement of its thermal capacity inside a container having the constant volume of 100 L shows that under these conditions, the thermal capacity (heat) capacity is constant and equal to 0.1 calories / K. Express the energy of the system as a function of T and V."
The first law: dQ = dU + dW.
Since we want U=U(T,V), we can express the first law as:
[tex]
\left(\frac{\partial Q}{\partial T}\right)_V dT + \left(\frac{\partial Q}{\partial V}\right)_T dV = \left(\frac{\partial U}{\partial T}\right)_V dT + [(\left(\frac{\partial U}{\partial V}\right)_T + (\frac{10^9*T^{1.1}}{V^{1.2}})] dV
[/tex]
We also know:
[tex]
\left(\frac{\partial U}{\partial V}\right)_T = T\left(\frac{\partial p}{\partial T}\right)_V - p
[/tex]
where again p can be substituted from the defined equation of state.
I'm tempted to say that [tex]\left(\frac{\partial Q}{\partial T}\right)_V = 0.1 cal / K [/tex] with the corresponding V = 100 L. If I do this and assume all dV = 0 for constant volume I get what appears to be a trivial result. I feel like I need to get a perfect differential to solve for U(T,V), but I don't see how. Other than that I haven't done much more than toy with the above equations. Thanks for your time.
Homework Statement
"A body obeys the equation of state:
pV[tex]^{1.2}[/tex] = 10[tex]^{9}[/tex]T[tex]^{1.1}[/tex]
A measurement of its thermal capacity inside a container having the constant volume of 100 L shows that under these conditions, the thermal capacity (heat) capacity is constant and equal to 0.1 calories / K. Express the energy of the system as a function of T and V."
Homework Equations
The first law: dQ = dU + dW.
Since we want U=U(T,V), we can express the first law as:
[tex]
\left(\frac{\partial Q}{\partial T}\right)_V dT + \left(\frac{\partial Q}{\partial V}\right)_T dV = \left(\frac{\partial U}{\partial T}\right)_V dT + [(\left(\frac{\partial U}{\partial V}\right)_T + (\frac{10^9*T^{1.1}}{V^{1.2}})] dV
[/tex]
We also know:
[tex]
\left(\frac{\partial U}{\partial V}\right)_T = T\left(\frac{\partial p}{\partial T}\right)_V - p
[/tex]
where again p can be substituted from the defined equation of state.
The Attempt at a Solution
I'm tempted to say that [tex]\left(\frac{\partial Q}{\partial T}\right)_V = 0.1 cal / K [/tex] with the corresponding V = 100 L. If I do this and assume all dV = 0 for constant volume I get what appears to be a trivial result. I feel like I need to get a perfect differential to solve for U(T,V), but I don't see how. Other than that I haven't done much more than toy with the above equations. Thanks for your time.