- #1
sankalpmittal
- 785
- 26
Homework Statement
A point object at 15 cm from a concave mirror of radius of curvature 20 cm is made to oscillate along principal axis with amplitude 2 mm. Find the amplitude of its image.
Homework Equations
Mirror formula :
1/v + 1/u = 1/f
Here u=-15 cm , f=-10
Differentiating above formula
dv/dt = -m2 du/dt
Where m= transverse magnification=-v/u
The Attempt at a Solution
Ok I don't know if it's SHM or just another sort of oscillatory motion. Had it been SHM I would have solved it by putting maximum velocity = amplitude times angular frequency.
SHM: Simple harmonic motion.
My attempt :
1/v + 1/u = 1/f
u=-15 cm , f=-10
v=-30
Thus m=-v/u = -2
Thus
dv/dt = -4 du/dt
Now ?
Please help !
Thanks in advance...