- #1
monty37
- 225
- 1
do tell me if the way i did this problem is right!
q::An object is thrown vertically upward with a velocity of 30m/s.Four seconds later
a second object is projected vertically with a velocity of 40 m/s .determine i)time(after first object is thrown)when two objects will meet each other in air ii) height from Earth when two objects meet
my probable solution:consider first object time as t and second object time as t+4,
solve for t by equating their maximum height formula(s=ut+0.5gt^2) ?
q::An object is thrown vertically upward with a velocity of 30m/s.Four seconds later
a second object is projected vertically with a velocity of 40 m/s .determine i)time(after first object is thrown)when two objects will meet each other in air ii) height from Earth when two objects meet
my probable solution:consider first object time as t and second object time as t+4,
solve for t by equating their maximum height formula(s=ut+0.5gt^2) ?