- #1
spikers220
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1. A 1 cm tall object sits 6cm to the left of a converging lens, f = 10 cm. A flat plane mirror sits 2 cm to the right of the lens. Light passes through the lens, reflects off the mirror, then back through the lens. Where is the final image? Real or Virtual? Upright or inverted? How big is it?
2. 1/f = 1/do+1/di
m = hi/ho = -di/do
3. The first thing that I did was calculate the di for the converging lens and got that to be -15 cm, which means that it will be on the same side as the object. I am kind of unsure on what to do next. Do I then take that image that was formed, make it a real object for the flat mirror, in which a virtual image forms 17cm behind the mirror? Then use 19 cm as the new object distance for my next calculation? It doesn't seem like that is the right thing to do.
I am new to forum so hopefully all this is clear.
2. 1/f = 1/do+1/di
m = hi/ho = -di/do
3. The first thing that I did was calculate the di for the converging lens and got that to be -15 cm, which means that it will be on the same side as the object. I am kind of unsure on what to do next. Do I then take that image that was formed, make it a real object for the flat mirror, in which a virtual image forms 17cm behind the mirror? Then use 19 cm as the new object distance for my next calculation? It doesn't seem like that is the right thing to do.
I am new to forum so hopefully all this is clear.