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DeerHunter
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Homework Statement
A cow, with a mass of 327 kg, if fired from a medieval catapault, and travels a horizontal distance of 1375 m. It lands in a depression 39 m below its starting position. If it is launched at an angle of 37.0[tex]\circ[/tex] above the horizontal, find its initial speed.
Givens
HOR
[tex]\Delta[/tex] dx= 1375
V1x= ?
ax= 0m/s2
v2x=v1x
VER
[tex]\Delta[/tex] dy= -39 m
v1y= ?
ay= -9.81m/s2
v2y=?
[tex]\Delta[/tex] T=?
Homework Equations
[tex]
v^2 = v_0^2 + 2 a \Delta x
[/tex]
[tex]
x = x_0 + v_0 t + (1/2) a t^2
[/tex]
[tex]
v^2 = v_0^2 + 2 a \Delta x
[/tex]
The Attempt at a Solution
I multiplied my vertical and horizontal displacements by 39.0* (i.e. dx= 1375*cos37) but I am not sure if this is right or if I should only use that for the velocity's only. Also I am not sure where to go from here all relevant equations require at least v1x,v2x,v1y,v2y and/or t. One last thing, I am not sure how mass is to be used as I am suppose to solve with kinematics, not forces but I could be wrong. Any help is appreciated! Thanks!