- #1
click0420
- 2
- 1
Homework Statement
find the angle of the projection for which the maximum height is equal to half of the range
Homework Equations
vertical: h =(vsinθ)t-0.5(g)(t^2)
horizontal: 2h =(vcosθ)t
The Attempt at a Solution
i know you set both equations equal to each other
(vsinθ)t -(0.5)(g)(t^2) = ((t)vcosθ)/2
cancel t
(vsinθ)-(0.5)(g)(t) = (vcosθ)/2
(2vsinθ-vcosθ)/2 = (0.5)(g)(t)
at this point i am slightly stuck, i know i need to sub some equivalent form in for "t" though i am not sure how/what formulas to use.