- #1
sunbunny
- 55
- 0
Hey, I'm having trouble with this problem:
A projectile is fired with an initial speed of 29.0 at an angle of 65.0 degrees above the horizontal. The object hits the ground
8.00s later.
How much higher or lower is the launch point relative to the point where the projectile hits the ground?
Express a launch point that is lower than the point where the projectile hits the ground as a negative number.
To what maximum height above the launch point does the projectile rise?
So I'm pretty sure I've drawn my diagram right, and now I've tried to set up an equation where:
distance x = (vcos)t and
distance y = (vsine)t -.5gt^2
when i put in the values from the question i get the wrong answers. if anyone could point me in the right direction and tell me waht I'm doing wrong that would be great.
Thanks!
A projectile is fired with an initial speed of 29.0 at an angle of 65.0 degrees above the horizontal. The object hits the ground
8.00s later.
How much higher or lower is the launch point relative to the point where the projectile hits the ground?
Express a launch point that is lower than the point where the projectile hits the ground as a negative number.
To what maximum height above the launch point does the projectile rise?
So I'm pretty sure I've drawn my diagram right, and now I've tried to set up an equation where:
distance x = (vcos)t and
distance y = (vsine)t -.5gt^2
when i put in the values from the question i get the wrong answers. if anyone could point me in the right direction and tell me waht I'm doing wrong that would be great.
Thanks!